Math Problem Statement

Find the distance between the points ( – 3,0) and ( – 2, – 6). Write your answer as a whole number or a fully simplified radical expression. Do not round. units

Solution

To find the distance between two points (3,0)(-3, 0) and (2,6)(-2, -6), we use the distance formula:

d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Step 1: Substitute the given points into the formula

Let: (x1,y1)=(3,0),(x2,y2)=(2,6)(x_1, y_1) = (-3, 0), \quad (x_2, y_2) = (-2, -6)

Substitute: d=((2)(3))2+((6)0)2d = \sqrt{((-2) - (-3))^2 + ((-6) - 0)^2}

Step 2: Simplify the differences

d=((2)+3)2+(60)2d = \sqrt{((-2) + 3)^2 + (-6 - 0)^2} d=(1)2+(6)2d = \sqrt{(1)^2 + (-6)^2}

Step 3: Square the terms

d=1+36d = \sqrt{1 + 36}

Step 4: Add the results

d=37d = \sqrt{37}

Final Answer:

37units.\boxed{\sqrt{37}} \, \text{units.}

Would you like a detailed explanation of any step or need help with similar problems? Here are some related questions:

  1. How do you derive the distance formula?
  2. What is the distance formula's connection to the Pythagorean theorem?
  3. Can you apply the formula to find the distance between two points in 3D space?
  4. What are some practical uses of the distance formula in geometry?
  5. How does the midpoint formula differ from the distance formula?

Tip: Always double-check signs when subtracting coordinates to avoid errors!

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Math Problem Analysis

Mathematical Concepts

Coordinate Geometry
Distance Formula

Formulas

Distance formula: d = √((x2 - x1)^2 + (y2 - y1)^2)

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 8-10