Math Problem Statement

The distance between Point A and Point B is 250 m. Point Z is located directly on the west of Point B. The distance between Point B and Point Z is 350 m. In the east of Point A, Point Y is there straight ahead. The distance between Point A and Point Y is the same as the distance from Point A to Point Z. Another point was established, namely Point J. Point J directly at the south of Point Y, whose distance from each other is twice as long as the distance of BY. Determine the distance between Point Z and Point J in meters.

Solution

Let's break down the problem step by step:

  1. Points and distances:

    • The distance between Point A and Point B is AB=250mAB = 250 \, \text{m}.
    • Point Z is located west of Point B, with a distance BZ=350mBZ = 350 \, \text{m}.
    • Point Y is east of Point A, and the distance between AYAY is the same as AZAZ, i.e., AY=AZAY = AZ.
    • The distance AZAZ is the sum of AB+BZ=250m+350m=600mAB + BZ = 250 \, \text{m} + 350 \, \text{m} = 600 \, \text{m}.
    • Therefore, AY=600mAY = 600 \, \text{m}.
  2. Point J:

    • Point J is located directly south of Point Y, and the distance between Point Y and Point J is twice the distance BYBY.
    • We can now calculate BYBY. Since AY=AZAY = AZ, and both BZBZ and BYBY are directly along the x-axis (B to Z and B to Y), we calculate BY=AB=250mBY = AB = 250 \, \text{m}.
    • The distance YJ=2×BY=2×250m=500mYJ = 2 \times BY = 2 \times 250 \, \text{m} = 500 \, \text{m}.
  3. Distance between Points Z and J:

    • We now need to determine the distance between Point Z (west of B) and Point J (south of Y). Since Z and J form a right triangle with the legs being:
      • ZZ to AA (horizontal distance): AZ=600mAZ = 600 \, \text{m}
      • JJ to YY (vertical distance): YJ=500mYJ = 500 \, \text{m}
  4. Using the Pythagorean theorem: ZJ=(AZ)2+(YJ)2=6002+5002=360000+250000=610000ZJ = \sqrt{(AZ)^2 + (YJ)^2} = \sqrt{600^2 + 500^2} = \sqrt{360000 + 250000} = \sqrt{610000} ZJ=610000781.02mZJ = \sqrt{610000} \approx 781.02 \, \text{m}

Thus, the distance between Point Z and Point J is approximately 781 meters.

Would you like further details or explanations?

Here are 5 related questions:

  1. How would the problem change if Point Z were to the north of Point B?
  2. What is the significance of the Pythagorean theorem in geometry problems like this?
  3. How would the distances change if Point J were to the west of Point Y instead of the south?
  4. Can you derive the formula for the distance between two points in 2D space?
  5. What if the distance between YY and JJ was three times BYBY?

Tip: In geometry problems involving distances, drawing a diagram to visualize the points and applying the Pythagorean theorem helps to solve complex setups easily.

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Math Problem Analysis

Mathematical Concepts

Geometry
Distance Calculation
Pythagorean Theorem

Formulas

Distance Formula: sqrt(x^2 + y^2)
Pythagorean Theorem: a^2 + b^2 = c^2

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 8-10