Math Problem Statement

what is the distance between k and J K is (0,-2) and J is (2,2)

Solution

To find the distance between two points K(0,2)K(0, -2) and J(2,2)J(2, 2), we use the distance formula:

d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Here, (x1,y1)=(0,2)(x_1, y_1) = (0, -2) and (x2,y2)=(2,2)(x_2, y_2) = (2, 2). Plugging these values into the formula:

d=(20)2+(2(2))2d = \sqrt{(2 - 0)^2 + (2 - (-2))^2} d=(2)2+(2+2)2d = \sqrt{(2)^2 + (2 + 2)^2} d=4+16d = \sqrt{4 + 16} d=20d = \sqrt{20} d=25d = 2\sqrt{5}

So, the distance between points KK and JJ is 252\sqrt{5}, approximately 4.474.47.

Would you like any further details or have questions?

Here are 5 related questions to explore:

  1. What is the midpoint between KK and JJ?
  2. How would you apply the distance formula in 3D space?
  3. What is the distance between two points along a vertical or horizontal line?
  4. Can you derive the distance formula from the Pythagorean theorem?
  5. How does the distance formula change for points on a coordinate plane with different units?

Tip: Always double-check signs when plugging coordinates into formulas to avoid simple errors!

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Math Problem Analysis

Mathematical Concepts

Geometry
Distance between two points
Coordinate Plane

Formulas

Distance formula: d = √((x2 - x1)^2 + (y2 - y1)^2)

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 7-9