Math Problem Statement

Tentukan dengan metode Direct Proof: 1) P₁: Jika A lulus ujian, maka A mendapat sertifikat. P₂: A tidak mendapat sertifikat. C: ... 2) Tentukan dalam Tabel Kebenaran: (P → ¬Q) ∨ (¬R ∧ P) 3) Ubah relasi berikut ke bentuk matriks (unsur 0 dan 1) dan jumlahkan setiap baris binery tersebut.

Solution

Let's work through the questions in the image.

1) Direct Proof:

We are given two statements:

  • P1P_1: Jika A lulus ujian, maka A mendapat sertifikat (If A passes the exam, then A receives a certificate).
  • P2P_2: A tidak mendapat sertifikat (A does not receive a certificate).

You are asked to determine the proof method based on these statements. This looks like a scenario for indirect proof, particularly modus tollens, where if AA does not receive a certificate, then AA must not have passed the exam. This aligns with CC, which likely represents the conclusion, i.e., "A tidak lulus ujian" (A did not pass the exam).

So, in this case:

  • CC: A tidak lulus ujian (A did not pass the exam).

2) Truth Table:

We are asked to determine the truth values for the logical expression: (P¬Q)(¬RP)(P \to \neg Q) \lor (\neg R \land P) Where \to denotes implication, \lor denotes disjunction (OR), \land denotes conjunction (AND), and ¬\neg denotes negation (NOT).

Let's define a truth table for this compound expression:

  • We will need to calculate truth values for the components P¬QP \to \neg Q, ¬RP\neg R \land P, and their final disjunction.

The table will involve evaluating for all possible values of PP, QQ, and RR (True and False).

3) Matrix Representation:

We are given a relation in the form of a bipartite graph, with elements on the left {2, 3, 4, 1} and elements on the right {36, 24, 28}.

We are asked to convert this to a binary matrix representation and sum each row.

The relation between the elements can be encoded in a binary matrix. For example:

  • If an element from the left is connected to an element from the right, we write 1 in the matrix, otherwise 0.

The matrix will look like this:

362428
2111
3111
4011
1100

Now, summing each row:

  • Row 1: 1+1+1=31 + 1 + 1 = 3
  • Row 2: 1+1+1=31 + 1 + 1 = 3
  • Row 3: 0+1+1=20 + 1 + 1 = 2
  • Row 4: 1+0+0=11 + 0 + 0 = 1

Do you want more detailed calculations or clarifications?

5 Related Questions:

  1. How can we prove CC (the conclusion) using modus ponens instead of modus tollens?
  2. How do we interpret logical implications (PQP \to Q) in a truth table?
  3. What other logical identities could simplify the expression in question 2?
  4. Can relations be represented as graphs, and how do we transition between different forms (e.g., graph to matrix)?
  5. What is the significance of the row sums in a relation matrix?

Tip:

When working with truth tables, it's useful to break down complex logical expressions step by step, starting from the simplest components.

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Math Problem Analysis

Mathematical Concepts

Logic
Truth Tables
Binary Matrices
Relations

Formulas

P → Q (Implication)
¬ (Negation)
P ∧ Q (Conjunction)
P ∨ Q (Disjunction)

Theorems

Modus Tollens
Modus Ponens

Suitable Grade Level

Grades 11-12