You need 500 ml of 70% ethyl alcohol. You only have in stock a bottle of 95% ethyl alcohol.
How many milliliters of 95% ethyl alcohol and water would you need to make your new solution?
6

To make a 500 mL solution of 70% ethyl alcohol using 95% ethyl alcohol, we can use the formula for dilution:

\[
C_1 V_1 = C_2 V_2
\]

Where:
- \(C_1\) is the concentration of the stock solution (95%).
- \(V_1\) is the volume of the stock solution needed (what we are solving for).
- \(C_2\) is the concentration of the final solution (70%).
- \(V_2\) is the final volume of the solution (500 mL).

Substituting the values:

\[
95\% \cdot V_1 = 70\% \cdot 500
\]

\[
0.95 \cdot V_1 = 0.70 \cdot 500
\]

Now, solving for \(V_1\):

\[
V_1 = \frac{0.70 \cdot 500}{0.95}
\]

Let me calculate this value.

You would need approximately 368.42 mL of 95% ethyl alcohol.

To make up the rest of the 500 mL solution, you would need:

\[
500 - 368.42 = 131.58 \, \text{mL of water}.
\]

Thus, you need:
- 368.42 mL of 95% ethyl alcohol.
- 131.58 mL of water.

Would you like more details, or do you have any questions?

Here are 5 related questions:
1. How would the calculation change if the final concentration required was 80%?
2. What would be the impact if the stock solution was only 90% alcohol?
3. Can you derive the formula used in dilution problems like this one?
4. What is the importance of the final volume in dilution calculations?
5. How does the dilution of solutions affect the properties of the final mixture?

**Tip:** Always ensure to mix the alcohol and water thoroughly to achieve a uniform solution.

You need 500 ml of 70% ethyl alcohol. You only have in stock a bottle of 95% ethyl alcohol. How many milliliters of 95% ethyl alcohol and water would you need to make your new solution?

Learn how to dilute 95% ethyl alcohol to 70% using the dilution formula C1V1 = C2V2. This problem explains how to make 500 mL of a 70% ethyl alcohol solution by mixing the correct amounts of 95% alcohol and water. Suitable for students in Grades 9-12.

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