Math Problem Statement
Solution
Let's work through the given problems:
(a) Differentiate with respect to
(i)
To differentiate this, we will use the product rule and chain rule.
The product rule states: where and .
- , so .
- , and by the chain rule, .
Using the product rule: Thus, the derivative is:
(ii)
This requires the quotient rule and chain rule.
The quotient rule is: where and .
- , and by the chain rule, .
- , so .
Now applying the quotient rule: Simplifying: Thus, the derivative is:
(b) Given , find in terms of .
We will use implicit differentiation. Differentiate both sides with respect to :
The left side is:
The right side requires the chain rule:
Thus, we have:
Solving for :
To express in terms of , recall that , so:
Using the identity , we can solve for :
Substitute into the equation for :
Thus, the final result is:
Would you like any additional details or explanations? Here are some follow-up questions you might find helpful:
- How does the product rule work when differentiating products of functions?
- What is the chain rule, and how does it apply in these problems?
- Can you explain the quotient rule in further detail with an example?
- How does implicit differentiation differ from regular differentiation?
- What are the main trigonometric identities used in calculus?
Tip: When differentiating complex functions, always break them down step by step using the product, quotient, or chain rule to avoid mistakes!
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Math Problem Analysis
Mathematical Concepts
Differentiation
Product Rule
Quotient Rule
Chain Rule
Implicit Differentiation
Trigonometry
Formulas
Product Rule: (d/dx)(uv) = u'v + uv'
Quotient Rule: (d/dx)(u/v) = (v * u' - u * v') / v^2
Chain Rule: d/dx(f(g(x))) = f'(g(x)) * g'(x)
Implicit Differentiation: d/dx(f(x, y)) using dy/dx
Theorems
Chain Rule
Product Rule
Quotient Rule
Trigonometric Identities
Suitable Grade Level
Grades 11-12 or College Level
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