Math Problem Statement

Find the difference quotient for the function f(x) = 3x + 4.

Solution

To solve the difference quotient for the given function f(x)=3x+4f(x) = 3x + 4, we need to compute:

f(x+h)f(x)h\frac{f(x+h) - f(x)}{h}

Step-by-step solution:

  1. Find f(x+h)f(x + h): Substitute x+hx + h into the function f(x)=3x+4f(x) = 3x + 4: f(x+h)=3(x+h)+4=3x+3h+4f(x + h) = 3(x + h) + 4 = 3x + 3h + 4

  2. Compute the difference f(x+h)f(x)f(x + h) - f(x): Now subtract f(x)f(x) from f(x+h)f(x + h): f(x+h)f(x)=(3x+3h+4)(3x+4)=3x+3h+43x4=3hf(x + h) - f(x) = (3x + 3h + 4) - (3x + 4) = 3x + 3h + 4 - 3x - 4 = 3h

  3. Simplify the difference quotient: Now divide by hh: f(x+h)f(x)h=3hh=3\frac{f(x+h) - f(x)}{h} = \frac{3h}{h} = 3

Thus, the simplified difference quotient is:

f(x+h)f(x)h=3\frac{f(x+h) - f(x)}{h} = 3

Would you like further clarification or more details on this process?

Here are 5 related questions to consider:

  1. How does the difference quotient relate to the concept of a derivative?
  2. Can we apply the difference quotient to non-linear functions, and how would the process differ?
  3. What is the geometric interpretation of the difference quotient for a linear function like f(x)=3x+4f(x) = 3x + 4?
  4. How does the constant term (like the +4+4 in this function) affect the difference quotient?
  5. How can we use the difference quotient to approximate instantaneous rates of change?

Tip: The difference quotient is essentially the average rate of change over an interval, and it's a key step in finding the derivative of a function.

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Math Problem Analysis

Mathematical Concepts

Algebra
Difference Quotient
Linear Functions

Formulas

Difference Quotient: \frac{f(x+h) - f(x)}{h}
Function: f(x) = 3x + 4

Theorems

Difference Quotient Theorem

Suitable Grade Level

Grades 9-12