Math Problem Statement

Find the difference quotient for the function f(x) = 4x + 7. Simplify your answer as much as possible.

Solution

To solve this problem, we need to find the difference quotient for the given function f(x)=4x+7f(x) = 4x + 7. The difference quotient is defined as:

f(x+h)f(x)h\frac{f(x+h) - f(x)}{h}

Step-by-step solution:

  1. Find f(x+h)f(x+h): Using the function f(x)=4x+7f(x) = 4x + 7, replace xx with x+hx+h:

    f(x+h)=4(x+h)+7=4x+4h+7f(x+h) = 4(x+h) + 7 = 4x + 4h + 7

  2. Subtract f(x)f(x) from f(x+h)f(x+h):

    f(x+h)f(x)=(4x+4h+7)(4x+7)f(x+h) - f(x) = (4x + 4h + 7) - (4x + 7) Simplifying this:

    f(x+h)f(x)=4x+4h+74x7=4hf(x+h) - f(x) = 4x + 4h + 7 - 4x - 7 = 4h

  3. Divide by hh:

    f(x+h)f(x)h=4hh=4\frac{f(x+h) - f(x)}{h} = \frac{4h}{h} = 4

Final Answer:

The simplified difference quotient is 4\boxed{4}.

Would you like more details on this, or do you have any questions?

Here are 5 related questions to deepen your understanding:

  1. What is the geometric meaning of the difference quotient in relation to the slope of a line?
  2. How does the difference quotient change if the function is quadratic, for example f(x)=x2f(x) = x^2?
  3. Why does the constant term 77 in the function f(x)=4x+7f(x) = 4x + 7 not affect the difference quotient?
  4. How can the difference quotient be used to approximate the derivative of a function?
  5. What happens to the difference quotient as hh approaches 0?

Tip: The difference quotient is a foundational concept in calculus because it leads to the derivative, which represents the instantaneous rate of change or the slope of the tangent line at a point.

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Math Problem Analysis

Mathematical Concepts

Difference Quotient
Linear Functions
Algebra

Formulas

Difference Quotient: (f(x + h) - f(x)) / h
f(x) = 4x + 7

Theorems

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Suitable Grade Level

Grades 10-12