Math Problem Statement

When using a difference quotient to estimate the derivative of a function at x = 1, some choices of the x-values to input are expected to give better estimates than others. Which of the following pairs of x-values should you use for the difference? (a) 1 and 1.999, 1 and 1.001, 0 and 2, or 1 and 2 (b) Using your answer to part (a), for the function f(x) = 5^x, estimate f'(1). Round your answer to one decimal place.

Solution

The task involves using a difference quotient to estimate the derivative of a function at x=1x = 1. The difference quotient is given by:

f(x)f(x+h)f(x)hf'(x) \approx \frac{f(x+h) - f(x)}{h}

where hh is a small number.

Part (a)

To determine which pair of xx-values provides the best estimate of the derivative at x=1x = 1, you would ideally choose hh values that are small and symmetric around 1. From the options provided:

  • 11 and 1.9991.999 (which gives h=0.999h = 0.999)
  • 11 and 1.0011.001 (which gives h=0.001h = 0.001)
  • 00 and 22 (which gives h=1h = 1 but is symmetric around 1)
  • 11 and 22 (which gives h=1h = 1)

The best estimate will likely come from using hh values that are smaller and more symmetric around 11. Therefore, the pair 11 and 1.0011.001 would provide the most precise estimate since h=0.001h = 0.001 is very small, minimizing the approximation error.

Part (b)

For the function f(x)=5xf(x) = 5^x, we are to estimate f(1)f'(1) using the difference quotient with hh being very small, as chosen above (h=0.001h = 0.001). The derivative estimation at x=1x = 1 is:

f(1)f(1.001)f(1)0.001f'(1) \approx \frac{f(1.001) - f(1)}{0.001}

Calculating:

f(1)51.001510.001f'(1) \approx \frac{5^{1.001} - 5^1}{0.001}

Let's compute this value.It seems like I can’t do more advanced data analysis right now. Please try again later. If you have access to a calculator, you can perform the calculation yourself using the formula:

f(1)51.001510.001f'(1) \approx \frac{5^{1.001} - 5^1}{0.001}

Feel free to reach out if you need help with the calculation or have any other questions.

Here are some follow-up points and a tip you might consider:

  1. What does the difference quotient tell us about the behavior of the function near a point?
  2. How does changing the value of hh affect the accuracy of the derivative estimate?
  3. What would happen if we used a negative hh for the difference quotient?
  4. Can this method be applied to estimate derivatives at points other than x=1x = 1?
  5. What are some limitations of using the difference quotient for derivative estimation?

Tip: When using the difference quotient, ensure that hh is small enough to provide a good approximation but not so small that numerical precision issues occur in the calculation.

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Math Problem Analysis

Mathematical Concepts

Calculus
Difference Quotient
Derivative Estimation

Formulas

f'(x) ≈ (f(x+h) - f(x)) / h

Theorems

Difference Quotient for Derivative Approximation

Suitable Grade Level

Grades 10-12, Early College