Math Problem Statement

if f(x)=5^x, then (f(x+h)-f(x))/h =

Solution

Given the function f(x)=5xf(x) = 5^x, we want to find the expression for the difference quotient:

f(x+h)f(x)h\frac{f(x+h) - f(x)}{h}

Step-by-Step Calculation:

  1. Substitute the Function:

    Substitute f(x)=5xf(x) = 5^x into the difference quotient:

    5x+h5xh\frac{5^{x+h} - 5^x}{h}

  2. Apply Properties of Exponents:

    Recall that 5x+h=5x5h5^{x+h} = 5^x \cdot 5^h. Using this, we rewrite the expression:

    5x5h5xh\frac{5^x \cdot 5^h - 5^x}{h}

  3. Factor Out Common Terms:

    Factor out 5x5^x from the numerator:

    =5x(5h1)h= \frac{5^x (5^h - 1)}{h}

Simplified Difference Quotient:

The difference quotient for f(x)=5xf(x) = 5^x is:

f(x+h)f(x)h=5x(5h1)h\frac{f(x+h) - f(x)}{h} = \frac{5^x (5^h - 1)}{h}

Interpretation:

  • This expression represents the average rate of change of 5x5^x over an interval of hh.
  • If you take the limit as h0h \to 0, this expression will give the derivative of f(x)=5xf(x) = 5^x.

Would you like to see the derivative calculation using this quotient?

Related Questions:

  1. How do you find the derivative of 5x5^x using limits?
  2. Why is the difference quotient important in calculus?
  3. How does the expression change if f(x)=axf(x) = a^x for a different base aa?
  4. What is the derivative of exponential functions in general?
  5. What happens to the difference quotient as h0h \to 0?

Tip: Knowing the difference quotient is fundamental in understanding how a function changes, leading to the concept of the derivative in calculus.

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Math Problem Analysis

Mathematical Concepts

Exponential Functions
Difference Quotient
Limits

Formulas

Difference quotient formula

Theorems

Limit definition of derivative

Suitable Grade Level

Grades 11-12