Math Problem Statement

f1=200N to the right and angle 45 degrees with positive y axis. F2= 150N and angle 30 degrees with positive x axis. determine x and y components of F1 and F2. determine the magnitude of the resultant force and its direction measured counterclockwise from the positive axis

Solution

Let's break this problem down step by step:

Step 1: Resolve Forces into Components

Each force can be resolved into its x-component and y-component using trigonometric functions.

Force F1=200NF_1 = 200N

  • Angle = 45° with the positive y-axis.
  • Components:
    • F1x=F1sin45=200×sin45F_{1x} = F_1 \sin 45^\circ = 200 \times \sin 45^\circ
    • F1y=F1cos45=200×cos45F_{1y} = F_1 \cos 45^\circ = 200 \times \cos 45^\circ

Force F2=150NF_2 = 150N

  • Angle = 30° with the positive x-axis.
  • Components:
    • F2x=F2cos30=150×cos30F_{2x} = F_2 \cos 30^\circ = 150 \times \cos 30^\circ
    • F2y=F2sin30=150×sin30F_{2y} = F_2 \sin 30^\circ = 150 \times \sin 30^\circ

Now, let's calculate these values. math

Given forces and angles

F1 = 200 # N theta1 = 45 # degrees (with positive y-axis) F2 = 150 # N theta2 = 30 # degrees (with positive x-axis)

Components of F1

F1x = F1 * math.sin(math.radians(theta1)) F1y = F1 * math.cos(math.radians(theta1))

Components of F2

F2x = F2 * math.cos(math.radians(theta2)) F2y = F2 * math.sin(math.radians(theta2))

F1x, F1y, F2x, F2yThe force components are:

  • F1x=141.42NF_{1x} = 141.42N, F1y=141.42NF_{1y} = 141.42N
  • F2x=129.90NF_{2x} = 129.90N, F2y=75.00NF_{2y} = 75.00N

Step 2: Find the Resultant Force Components

The resultant force components are:

Rx=F1x+F2xR_x = F_{1x} + F_{2x} Ry=F1y+F2yR_y = F_{1y} + F_{2y}

Now, let's compute these values. Resultant force components Rx = F1x + F2x Ry = F1y + F2y

Rx, RyThe resultant force components are:

  • Rx=271.33NR_x = 271.33N
  • Ry=216.42NR_y = 216.42N

Step 3: Find the Magnitude of the Resultant Force

The magnitude of the resultant force is given by:

R=Rx2+Ry2R = \sqrt{R_x^2 + R_y^2}

Let's calculate this. Magnitude of the resultant force R = math.sqrt(Rx2 + Ry2) RThe magnitude of the resultant force is 347.07N.

Step 4: Find the Direction of the Resultant Force

The direction (angle counterclockwise from the positive x-axis) is given by:

θ=tan1(RyRx)\theta = \tan^{-1} \left( \frac{R_y}{R_x} \right)

Let's compute this. Direction of the resultant force (angle counterclockwise from positive x-axis) theta = math.degrees(math.atan(Ry / Rx)) thetaIt seems like I can’t do more advanced data analysis right now. Please try again later. However, you can calculate the angle manually using:

θ=tan1(216.42271.33)\theta = \tan^{-1} \left( \frac{216.42}{271.33} \right)

Would you like me to guide you through the manual calculation, or do you have any other questions?

Here are some related questions you might find useful:

  1. How do I resolve forces in different quadrants?
  2. What is the significance of force components in engineering?
  3. How does the resultant force affect motion in mechanics?
  4. Can I use a graphical method to find the resultant force?
  5. What happens if one of the forces acts in the opposite direction?

Tip: Always double-check angle conventions when resolving forces, as they depend on the reference axis used!

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Math Problem Analysis

Mathematical Concepts

Vector Decomposition
Trigonometry
Resultant Force
Force Components

Formulas

F1x = F1 * sin(θ1)
F1y = F1 * cos(θ1)
F2x = F2 * cos(θ2)
F2y = F2 * sin(θ2)
Rx = F1x + F2x
Ry = F1y + F2y
R = sqrt(Rx^2 + Ry^2)
θ = atan(Ry / Rx)

Theorems

Law of Cosines
Pythagorean Theorem

Suitable Grade Level

Grades 10-12