Math Problem Statement

Determine the quadratic function of the form f(x) = a(x - h)^2 + k whose graph is given with vertex at (2, -3) and passing through the point (-1, 2).

Solution

To determine the quadratic function f(x)=a(xh)2+kf(x) = a(x - h)^2 + k for the given graph, we need to identify the vertex and use additional points to solve for aa.

Step 1: Identify the Vertex (h,k)(h, k)

From the graph, we can see the vertex is at (2,3)(2, -3). Therefore:

  • h=2h = 2
  • k=3k = -3

So far, the function looks like: f(x)=a(x2)23f(x) = a(x - 2)^2 - 3

Step 2: Use Another Point to Find aa

We’ll use the point (1,2)(-1, 2) to find aa. Substitute x=1x = -1 and f(x)=2f(x) = 2 into the equation: 2=a(12)232 = a(-1 - 2)^2 - 3 2=a(3)232 = a(3)^2 - 3 2=9a32 = 9a - 3 Add 3 to both sides: 5=9a5 = 9a Divide by 9: a=59a = \frac{5}{9}

Final Equation

Now, substitute a=59a = \frac{5}{9}, h=2h = 2, and k=3k = -3 back into the equation: f(x)=59(x2)23f(x) = \frac{5}{9}(x - 2)^2 - 3

So, the quadratic function is: f(x)=59(x2)23f(x) = \frac{5}{9}(x - 2)^2 - 3

Would you like further details or have any questions?


Here are some related questions to consider:

  1. How can we determine the axis of symmetry from the vertex form of a quadratic function?
  2. What are other methods to convert a quadratic function to standard form?
  3. How does changing the value of aa affect the graph of the function?
  4. How can we find the x-intercepts of this quadratic function?
  5. How does the vertex form make it easier to graph parabolas?

Tip: Remember that the vertex form of a quadratic function makes it easy to read the vertex (h,k)(h, k) directly from the equation!

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations
Vertex Form

Formulas

f(x) = a(x - h)^2 + k

Theorems

Vertex form of a quadratic function

Suitable Grade Level

Grades 9-11