Math Problem Statement

A wooden block stretched the spring so the hanger was 24.2 cm off the ground. Determine the mass of the wooden block, to at least 1 decimal place.

Solution

The problem discusses how a string stretches linearly with the mass applied. We are given the following information:

  • No additional mass: the hanger is 30.6 cm off the ground.
  • With 150 grams of mass: the hanger is 16.2 cm off the ground.

We are asked to find the mass of a wooden block that causes the hanger to be 24.2 cm off the ground.

Step-by-step solution:

  1. Define the relationship: Since the stretch varies linearly with mass, we can assume the position of the hanger follows the equation of a line: h=h0kmh = h_0 - k \cdot m where:

    • hh is the height of the hanger off the ground,
    • h0h_0 is the initial height (30.6 cm when no mass is added),
    • kk is the rate of change (slope) of the height with mass,
    • mm is the mass in grams.
  2. Find the slope kk: Using the two given points, (0grams,30.6cm)(0 \, \text{grams}, 30.6 \, \text{cm}) and (150grams,16.2cm)(150 \, \text{grams}, 16.2 \, \text{cm}), we can calculate the slope kk: k=30.616.20150=14.4150=0.096cm/gramk = \frac{30.6 - 16.2}{0 - 150} = \frac{14.4}{-150} = -0.096 \, \text{cm/gram}

  3. Write the equation: Now, we have the equation of the line: h=30.60.096mh = 30.6 - 0.096 \cdot m

  4. Determine the mass of the wooden block: We are given that the wooden block stretches the spring to a height of 24.2 cm. Substitute h=24.2h = 24.2 into the equation and solve for mm: 24.2=30.60.096m24.2 = 30.6 - 0.096 \cdot m 0.096m=30.624.2=6.40.096 \cdot m = 30.6 - 24.2 = 6.4 m=6.40.096=66.67gramsm = \frac{6.4}{0.096} = 66.67 \, \text{grams}

So, the mass of the wooden block is approximately 66.7 grams.

Would you like further details or clarifications? Here are 5 questions you could explore:

  1. How does the spring constant relate to the slope of the line in this problem?
  2. What would happen to the equation if the mass varied non-linearly with height?
  3. Can you graph the relationship between the mass and height for this spring system?
  4. How would the system behave if you used a heavier block? Would the spring obey Hooke's law indefinitely?
  5. Could the spring’s material impact the linearity of its stretch?

Tip: Linear relationships like this one can often be solved using the concept of proportionality, which simplifies many real-world physics problems.

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Math Problem Analysis

Mathematical Concepts

Linear equations
Proportionality
Algebra

Formulas

h = h_0 - k * m (linear relationship between mass and height)
Slope formula: k = (h_1 - h_2) / (m_1 - m_2)

Theorems

Linear variation principle

Suitable Grade Level

Grades 9-11