Math Problem Statement

solve it

Determine the domain and range of the given relation. Is the relation a function?

Solution

Let's go through each part systematically. For every part, we will:

  1. List the Domain: The set of all first components (x-values).
  2. List the Range: The set of all second components (y-values).
  3. Check if it's a Function: If every x-value maps to exactly one y-value, the relation is a function. Otherwise, it is not.

(a) {(4,3),(2,5),(4,6),(2,0)}\{(-4, -3), (2, -5), (4, 6), (2, 0)\}

  • Domain: {4,2,4}\{-4, 2, 4\}
  • Range: {3,5,6,0}\{-3, -5, 6, 0\}
  • Is it a Function?
    No, because x=2x = 2 is mapped to both 5-5 and 00.

(b) {(8,2),(6,32),(1,5)}\{(8, -2), (6, -\frac{3}{2}), (-1, 5)\}

  • Domain: {8,6,1}\{8, 6, -1\}
  • Range: {2,32,5}\{-2, -\frac{3}{2}, 5\}
  • Is it a Function?
    Yes, each x-value has a unique y-value.

(c) {(3,3),(1.1,0),(0,0),(1.1,1.1),(3,3)}\left\{(-\sqrt{3}, 3), (-1.1, 0), (0, 0), (1.1, 1.1), (\sqrt{3}, 3)\right\}

  • Domain: {3,1.1,0,1.1,3}\{-\sqrt{3}, -1.1, 0, 1.1, \sqrt{3}\}
  • Range: {3,0,1.1}\{3, 0, 1.1\}
  • Is it a Function?
    No, because both x=3x = -\sqrt{3} and x=3x = \sqrt{3} map to the same y=3y = 3.

(d) {(12,16),(1,1),(13,13)}\left\{\left(-\frac{1}{2}, \frac{1}{6}\right), (-1, 1), \left(\frac{1}{3}, \frac{1}{3}\right)\right\}

  • Domain: {12,1,13}\left\{-\frac{1}{2}, -1, \frac{1}{3}\right\}
  • Range: {16,1,13}\left\{\frac{1}{6}, 1, \frac{1}{3}\right\}
  • Is it a Function?
    Yes, each x-value maps to a unique y-value.

(e) {(0,5),(1,5),(2,5),(3,5),(4,5),(5,5)}\{(0, 5), (1, 5), (2, 5), (3, 5), (4, 5), (5, 5)\}

  • Domain: {0,1,2,3,4,5}\{0, 1, 2, 3, 4, 5\}
  • Range: {5}\{5\}
  • Is it a Function?
    Yes, each x-value has a unique y-value (even though all map to 5).

(f) {(5,0),(5,1),(5,2),(5,3),(5,4),(5,5)}\{(5, 0), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5)\}

  • Domain: {5}\{5\}
  • Range: {0,1,2,3,4,5}\{0, 1, 2, 3, 4, 5\}
  • Is it a Function?
    No, because x=5x = 5 maps to multiple y-values (0, 1, 2, 3, 4, 5).

Summary

PartDomainRangeIs it a Function?
(a){4,2,4}\{-4, 2, 4\}{3,5,6,0}\{-3, -5, 6, 0\}No
(b){8,6,1}\{8, 6, -1\}{2,32,5}\{-2, -\frac{3}{2}, 5\}Yes
(c){3,1.1,0,1.1,3}\{-\sqrt{3}, -1.1, 0, 1.1, \sqrt{3}\}{3,0,1.1}\{3, 0, 1.1\}No
(d){12,1,13}\left\{-\frac{1}{2}, -1, \frac{1}{3}\right\}{16,1,13}\left\{\frac{1}{6}, 1, \frac{1}{3}\right\}Yes
(e){0,1,2,3,4,5}\{0, 1, 2, 3, 4, 5\}{5}\{5\}Yes
(f){5}\{5\}{0,1,2,3,4,5}\{0, 1, 2, 3, 4, 5\}No

Do you have any further questions or want more details on specific parts?

5 Related Questions

  1. What makes a relation not a function?
  2. How is the domain different from the range?
  3. Can a function have repeated y-values?
  4. What is the difference between a function and a one-to-one function?
  5. How do you determine the range when graphing a function?

Tip

Always check for repeated x-values with different y-values to quickly identify whether a relation is a function.

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Math Problem Analysis

Mathematical Concepts

Relations
Domain and Range
Functions

Formulas

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Theorems

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Suitable Grade Level

Grade 9-12