Math Problem Statement

What is the amplitude and period of this graph

What is the amplitude and period of this graph?

Solution

From the given image of the graph, we can determine the following:

Amplitude:

The amplitude is the maximum vertical distance from the centerline (midpoint of the wave) to the peak or trough. From the graph:

  • The maximum value is 2.
  • The minimum value is -2.
  • The amplitude is therefore: Amplitude=Maximum valueMinimum value2=2(2)2=2\text{Amplitude} = \frac{\text{Maximum value} - \text{Minimum value}}{2} = \frac{2 - (-2)}{2} = 2

Period:

The period is the horizontal distance it takes for the wave to complete one full cycle. From the graph:

  • A full cycle starts at -5, returns to the same position at -1, and continues similarly.
  • The period is therefore: Period=1(5)=4\text{Period} = | -1 - (-5) | = 4

Final Results:

  • Amplitude: 22
  • Period: 44

Do you have any questions or want further details?

Here are five related questions:

  1. What is the equation of the wave given its amplitude and period?
  2. How can the phase shift be determined from the graph?
  3. What is the frequency of the wave, given the period?
  4. How do we adjust the amplitude or period in a sine or cosine function?
  5. What are some real-world applications of sinusoidal graphs like this one?

Tip: To calculate the period of any sinusoidal wave, use the formula Period=2πb\text{Period} = \frac{2\pi}{b}, where bb is the coefficient of xx in the function.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Graph Analysis
Periodic Functions

Formulas

Amplitude = (Maximum value - Minimum value) / 2
Period = Distance for one full cycle of the wave

Theorems

Properties of Sine and Cosine Waves

Suitable Grade Level

Grades 9-12