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The problem can be broken down and solved using algebra. Let's define the distance Desmond ran each day:

- On Monday, Desmond ran **x** kilometers.
- On Tuesday, he ran 3 kilometers less than on Monday, which is **x - 3** kilometers.
- On Wednesday, he ran 4 times the distance he ran on Monday, which is **4x** kilometers.

The average (mean) distance over these three days is given as 16 kilometers. The formula for the mean is:

\[
\text{Mean} = \frac{\text{Sum of distances}}{3}
\]

So, we can set up the equation based on the total distance Desmond ran over the three days:

\[
\frac{x + (x - 3) + 4x}{3} = 16
\]

Now, let's solve this equation.

\[
x + (x - 3) + 4x = 48
\]
\[
6x - 3 = 48
\]
\[
6x = 51
\]
\[
x = \frac{51}{6} = 8.5
\]

Thus, on Monday, Desmond ran **8.5 kilometers**.

Now, let's calculate how far he ran on Wednesday:

\[
\text{Wednesday distance} = 4x = 4 \times 8.5 = 34 \text{ kilometers}
\]

Therefore, Desmond ran **34 kilometers** on Wednesday.

Do you need more details, or have any questions?

Here are 5 related questions for further practice:
1. What if Desmond had run 5 kilometers less on Tuesday instead of 3? How would that affect the Wednesday run?
2. If the mean distance was instead 20 kilometers, how far would Desmond have run on Monday?
3. What is the total distance Desmond ran over the three days?
4. How would the calculation change if Desmond ran double the distance on Wednesday compared to Monday?
5. If Desmond ran 3 times the distance on Wednesday, how far would he have run on Tuesday?

**Tip:** Always check your work by plugging the solution back into the original equation to ensure correctness.

On Monday, Desmond ran x kilometres. On Tuesday, he ran three kilometres less than Monday. On Wednesday, Desmond ran four times the distance he ran on Monday. The mean distance ran was 16 kilometres. Work out how far Desmond ran on Wednesday.

Solve this algebra problem where Desmond runs different distances over three days. The mean distance is 16 kilometers, and you need to calculate how far he ran on Wednesday. This problem involves algebra and calculating averages, suitable for students in Grades 7-9.

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