Math Problem Statement

Find derivatives of the functions defined as follows. Show step by step

Find the derivative of the function f(x) = e^{x \sqrt{3x + 2}}.

Solution

We are tasked with finding the derivative of the function f(x)=ex3x+2f(x) = e^{x \sqrt{3x + 2}}. Let's go step by step.

Function:

f(x)=ex3x+2f(x) = e^{x \sqrt{3x + 2}}

Step 1: Use the chain rule

Since the function is in the form f(x)=eg(x)f(x) = e^{g(x)}, where g(x)=x3x+2g(x) = x \sqrt{3x + 2}, the derivative of eg(x)e^{g(x)} is:

f(x)=eg(x)g(x)f'(x) = e^{g(x)} \cdot g'(x)

So, we need to find g(x)g'(x), where g(x)=x3x+2g(x) = x \sqrt{3x + 2}.

Step 2: Apply product and chain rule to g(x)g(x)

We can see that g(x)=x3x+2g(x) = x \sqrt{3x + 2} is a product of two functions, xx and 3x+2\sqrt{3x + 2}. Use the product rule:

g(x)=ddx(x)3x+2+xddx(3x+2)g'(x) = \frac{d}{dx} \left( x \right) \cdot \sqrt{3x + 2} + x \cdot \frac{d}{dx} \left( \sqrt{3x + 2} \right)

Step 3: Differentiate 3x+2\sqrt{3x + 2}

Now, differentiate 3x+2\sqrt{3x + 2}. Using the chain rule:

ddx(3x+2)=123x+23=323x+2\frac{d}{dx} \left( \sqrt{3x + 2} \right) = \frac{1}{2\sqrt{3x + 2}} \cdot 3 = \frac{3}{2\sqrt{3x + 2}}

Step 4: Apply product rule

Now substitute back into the product rule:

g(x)=13x+2+x323x+2=3x+2+3x23x+2g'(x) = 1 \cdot \sqrt{3x + 2} + x \cdot \frac{3}{2\sqrt{3x + 2}} = \sqrt{3x + 2} + \frac{3x}{2\sqrt{3x + 2}}

Simplify by getting a common denominator:

g(x)=2(3x+2)+3x23x+2=6x+4+3x23x+2=9x+423x+2g'(x) = \frac{2(3x + 2) + 3x}{2\sqrt{3x + 2}} = \frac{6x + 4 + 3x}{2\sqrt{3x + 2}} = \frac{9x + 4}{2\sqrt{3x + 2}}

Step 5: Compute f(x)f'(x)

Now, substitute g(x)g'(x) into the derivative formula for f(x)f(x):

f(x)=ex3x+29x+423x+2f'(x) = e^{x \sqrt{3x + 2}} \cdot \frac{9x + 4}{2\sqrt{3x + 2}}

Thus, the derivative of the function is:

f(x)=ex3x+29x+423x+2f'(x) = e^{x \sqrt{3x + 2}} \cdot \frac{9x + 4}{2\sqrt{3x + 2}}

Would you like further details on any part of the process?

Here are 5 follow-up questions related to this problem:

  1. What is the chain rule and how is it applied in this case?
  2. Can you explain how the product rule works in differentiating g(x)g(x)?
  3. Why do we need to simplify the derivative of 3x+2\sqrt{3x + 2}?
  4. What is the significance of exponential functions when differentiating?
  5. How would the derivative change if the exponent were a different function?

Tip: When differentiating products of functions, always check if either the product rule or chain rule applies to simplify your steps.

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Math Problem Analysis

Mathematical Concepts

Calculus
Derivatives
Exponential Functions
Product Rule
Chain Rule

Formulas

Chain rule: (f(g(x)))' = f'(g(x)) * g'(x)
Product rule: (uv)' = u'v + uv'
Derivative of e^g(x): e^g(x) * g'(x)

Theorems

Chain Rule
Product Rule

Suitable Grade Level

Advanced High School (Grades 11-12) or Undergraduate Calculus