Math Problem Statement

(x23x=0)(x^2-3x=0)'

Solution

To find the derivative of the function f(x)=x23xf(x) = x^2 - 3x, we apply the rules of differentiation.

The function is: f(x)=x23xf(x) = x^2 - 3x

Using the power rule, which states that ddx(xn)=nxn1\frac{d}{dx}(x^n) = nx^{n-1}, we differentiate each term separately.

  1. The derivative of x2x^2 is 2x2x.
  2. The derivative of 3x-3x is 3-3.

So, the derivative of the function is: f(x)=2x3f'(x) = 2x - 3

Therefore, the derivative of x23xx^2 - 3x is: (x23x)=2x3(x^2 - 3x)' = 2x - 3

Would you like more details or have any questions?

Here are some questions you might want to ask:

  1. How do you differentiate a product of functions?
  2. What is the chain rule in differentiation?
  3. How do you find the derivative of a trigonometric function?
  4. Can you explain implicit differentiation?
  5. How do you find the second derivative of a function?

Tip: Always remember to apply the differentiation rules to each term in the function separately before combining the results.

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Math Problem Analysis

Mathematical Concepts

Differentiation
Power rule

Formulas

Power rule for differentiation: \( \frac{d}{dx}(x^n) = nx^{n-1} \)

Theorems

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Suitable Grade Level

Grades 11-12