Math Problem Statement

Find the derivative of the function f(x) =x^2 -3 using the limit process

Solution

To find the derivative of the function f(x)=x23f(x) = x^2 - 3 using the limit definition of a derivative, we will apply the formula:

f(x)=limh0f(x+h)f(x)hf'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h}

Step-by-step process:

  1. Substitute f(x)=x23f(x) = x^2 - 3 into the limit definition:

f(x)=limh0(x+h)23(x23)hf'(x) = \lim_{h \to 0} \frac{(x+h)^2 - 3 - (x^2 - 3)}{h}

  1. Expand (x+h)2(x+h)^2:

(x+h)2=x2+2xh+h2(x+h)^2 = x^2 + 2xh + h^2

Now substitute this into the equation:

f(x)=limh0(x2+2xh+h23)(x23)hf'(x) = \lim_{h \to 0} \frac{(x^2 + 2xh + h^2 - 3) - (x^2 - 3)}{h}

  1. Simplify the expression:

First, cancel out common terms:

f(x)=limh0x2+2xh+h23x2+3hf'(x) = \lim_{h \to 0} \frac{x^2 + 2xh + h^2 - 3 - x^2 + 3}{h}

This simplifies to:

f(x)=limh02xh+h2hf'(x) = \lim_{h \to 0} \frac{2xh + h^2}{h}

  1. Factor out hh from the numerator:

f(x)=limh0h(2x+h)hf'(x) = \lim_{h \to 0} \frac{h(2x + h)}{h}

Cancel the hh:

f(x)=limh0(2x+h)f'(x) = \lim_{h \to 0} (2x + h)

  1. Evaluate the limit as h0h \to 0:

f(x)=2xf'(x) = 2x

Thus, the derivative of f(x)=x23f(x) = x^2 - 3 is:

f(x)=2xf'(x) = 2x

Would you like more details or have any questions?


Here are 5 related questions:

  1. How do you find the derivative of f(x)=x3f(x) = x^3 using the limit process?
  2. What is the derivative of f(x)=1xf(x) = \frac{1}{x} using the limit definition?
  3. Can you explain the difference between the power rule and the limit process for finding derivatives?
  4. What does the derivative of a constant function look like?
  5. How does the derivative of a quadratic function relate to its graph?

Tip: The limit definition of a derivative provides an intuitive understanding of how instantaneous rates of change are calculated.

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Math Problem Analysis

Mathematical Concepts

Calculus
Derivatives
Limit Process

Formulas

f'(x) = lim(h -> 0) [(f(x+h) - f(x)) / h]

Theorems

Limit Definition of Derivatives

Suitable Grade Level

Grades 11-12 (High School Calculus)