Math Problem Statement

Show all your work step by step as clearly as possible for BOTH multiple-choice and written questions. Otherwise, partial or full credit will not be given. 5 8. A machine worth $10,000 new and having a scrap value of $500 is to be depreciated over a ten-year life. Using the straight-line method for depreciation, answer the following questions. (7 points) A. What will be the value of the machine after 4 years? (3 points) B. At what time will the machine be worth $5,000? Round your answer to two decimal places. Answer: A.____________________ B. Approximately ____________________ years

Solution

To solve this depreciation problem using the straight-line method, we follow these steps:

Given:

  • Initial value of the machine (P) = $10,000
  • Scrap value (S) = $500
  • Lifespan of the machine (N) = 10 years

The straight-line method formula for depreciation is:

Annual Depreciation (D)=PSN\text{Annual Depreciation (D)} = \frac{P - S}{N}

In this case:

D=10,00050010=9,50010=950dollars per yearD = \frac{10,000 - 500}{10} = \frac{9,500}{10} = 950 \, \text{dollars per year}

The machine loses $950 in value every year.

Part A: What will be the value of the machine after 4 years?

The value of the machine after 4 years can be calculated by subtracting the depreciation for 4 years from the original value of the machine:

Value after 4 years=PD×4\text{Value after 4 years} = P - D \times 4

Substitute the values:

Value after 4 years=10,000950×4\text{Value after 4 years} = 10,000 - 950 \times 4 Value after 4 years=10,0003,800=6,200\text{Value after 4 years} = 10,000 - 3,800 = 6,200

Answer for Part A: $6,200


Part B: At what time will the machine be worth $5,000?

To find the time when the machine will be worth $5,000, we can use the formula for the machine's value after tt years:

Value at year t=PD×t\text{Value at year } t = P - D \times t

We are given the value at year tt is $5,000, so:

5,000=10,000950×t5,000 = 10,000 - 950 \times t

Now, solve for tt:

950×t=10,0005,000950 \times t = 10,000 - 5,000 950×t=5,000950 \times t = 5,000 t=5,0009505.26t = \frac{5,000}{950} \approx 5.26

Answer for Part B: Approximately 5.26 years


Final Answers:

  • Part A: $6,200
  • Part B: Approximately 5.26 years

Do you want further details or have any questions?

Here are 5 related questions:

  1. How is the depreciation formula derived?
  2. What would be the value after 7 years?
  3. What is the percentage depreciation per year?
  4. What happens if the scrap value changes?
  5. How is the straight-line method different from other depreciation methods?

Tip: Straight-line depreciation results in equal expense allocation over the asset's useful life.

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Math Problem Analysis

Mathematical Concepts

Depreciation
Straight-line Method
Algebra

Formulas

Annual Depreciation (D) = (P - S) / N
Value after t years = P - D × t

Theorems

Linear Depreciation

Suitable Grade Level

Grades 9-12