Math Problem Statement
Find a polynomial of the specified degree that satisfies the given conditions. Degree 4; zeros −1, 0, 4, 1,4 ; coefficient of x³ is 13
Solution
Given the problem where we need to find a degree 4 polynomial with the specified zeros and a coefficient of equal to 13, let's proceed with the following steps:
Step 1: Form the Polynomial
Since the polynomial has zeros at , , , and , we can express it as: where is a constant to be determined.
Step 2: Expand the Polynomial
First, we'll expand the factors:
- Multiply the first two factors: .
- Multiply the last two factors: .
Combining these results, we have:
Now, let's expand this expression:
Combining like terms:
So, the polynomial becomes:
Step 3: Determine the Constant
The coefficient of is given as 13, so we set up the equation:
Step 4: Write the Final Polynomial
Substituting into the polynomial:
Expanding this expression gives the final polynomial:
Final Answer:
The polynomial of degree 4 that satisfies the given conditions is:
Would you like further details or have any questions?
Here are some related questions to explore further:
- What is the effect of different roots on the shape of a polynomial graph?
- How can we determine the end behavior of polynomials of various degrees?
- What are the properties of polynomials when all roots are real versus when some are complex?
- How does the leading coefficient of a polynomial affect its graph?
- Can the degree of a polynomial be determined if not all roots are known?
Tip: When expanding polynomials, carefully combine like terms to simplify and verify the degree and coefficients of the resulting expression.
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Math Problem Analysis
Mathematical Concepts
Polynomial
Factoring
Expansion
Algebra
Formulas
Polynomial with roots: P(x) = k(x - r1)(x - r2)...(x - rn)
Expansion of product of binomials
Theorems
Factor Theorem
Zero Product Property
Suitable Grade Level
Grades 10-12
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