A 20% reduction in the price of bananas allows a consumer to buy 6 more bananas for Rs 80.  Find the decrease in price of bananas per dozen.

Let's solve this problem step-by-step.

1. **Let the original price of bananas per dozen be** \( x \) **Rs**.

2. Then, the original price per banana would be:
   \[
   \frac{x}{12} \text{ Rs}
   \]

3. After a 20% reduction, the new price per dozen becomes:
   \[
   x - \frac{20}{100} \cdot x = 0.8x
   \]

4. The new price per banana is then:
   \[
   \frac{0.8x}{12} \text{ Rs}
   \]

5. **According to the problem:** The consumer can buy 6 more bananas with the reduced price for Rs 80.

   Let \( n \) be the number of bananas bought at the reduced price, and then at the original price, they would be able to buy \( n - 6 \) bananas.

   So, we have:
   \[
   (n - 6) \cdot \frac{x}{12} = 80
   \]
   and
   \[
   n \cdot \frac{0.8x}{12} = 80
   \]

6. **Solving these two equations:** 

   Subtracting

A 20% reduction in the price of bananas allows a consumer to buy 6 more bananas for Rs 80. Find the decrease in price of bananas per dozen.

Solve a problem involving a 20% price reduction in bananas, where a consumer can buy 6 more bananas for Rs 80. Learn how to calculate the decrease in price per dozen with key algebraic concepts and step-by-step formulas. Suitable for students in Grades 9-10.

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