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To solve this problem, we can use the formula for electrical resistance \( R \) of a cylindrical material, which is given by:

\[
R = \frac{L}{\sigma A}
\]

Where:
- \( R \) is the resistance (in ohms, \( \Omega \)),
- \( L \) is the length of the cylinder (in meters),
- \( \sigma \) is the conductivity of the material (in \( \Omega^{-1} \cdot \text{m}^{-1} \)),
- \( A \) is the cross-sectional area (in square meters, \( \text{m}^2 \)).

### Given values:
- Length \( L = 0.15 \, \text{m} \),
- Cross-sectional area \( A = 240 \, \text{cm}^2 \) (we need to convert this to square meters),
- Conductivity \( \sigma = 0.24 \, \Omega^{-1} \cdot \text{m}^{-1} \).

First, let's convert the area from \( \text{cm}^2 \) to \( \text{m}^2 \):
\[
1 \, \text{cm}^2 = 1 \times 10^{-4} \, \text{m}^2
\]
\[
A = 240 \, \text{cm}^2 = 240 \times 10^{-4} \, \text{m}^2 = 0.024 \, \text{m}^2
\]

Now, we can calculate the resistance:
\[
R = \frac{L}{\sigma A} = \frac{0.15 \, \text{m}}{0.24 \, \Omega^{-1} \cdot \text{m}^{-1} \times 0.024 \, \text{m}^2}
\]

Simplifying:
\[
R = \frac{0.15}{0.24 \times 0.024} = \frac{0.15}{0.00576} \approx 26.04 \, \Omega
\]

### Final answer:
The resistance of the sample is approximately **26.0 ohms**.

Would you like more details on the steps or have any questions?

Here are some related questions to expand your understanding:
1. How does increasing the length of the material affect the resistance?
2. What is the relation between resistivity and conductivity?
3. How would the resistance change if the cross-sectional area was halved?
4. What units are commonly used to measure resistivity and conductivity?
5. How does temperature affect the resistance of a material?

**Tip:** Always ensure units are consistent when solving problems to avoid errors in calculations.

A cylindrical sample of material has a length of 0.15m, a cross-sectional area of 240 cm² and a conductivity of 0.24 Ω⁻¹m⁻¹. What is the resistance of the sample? Give your answer to one decimal place, in Ohms (Ω).

This problem involves calculating the resistance of a cylindrical sample using the formula R = L / (σ * A). With a length of 0.15m, cross-sectional area of 240 cm², and conductivity of 0.24 Ω⁻¹m⁻¹, the resistance is calculated step-by-step.

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