Math Problem Statement
Solution
The problem involves a circuit with eight identical resistors, each of resistance , arranged in a particular configuration. The circuit is connected to a voltage source of 120 V, and the internal resistance is negligible. We are asked to determine the total current through the circuit.
Steps to solve:
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Identify the Configuration: From the diagram, it appears that the resistors are arranged in two parallel groups, each consisting of four resistors in series.
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Calculate the Equivalent Resistance for Each Series Group:
- Each series group contains four resistors, so the total resistance for one series group is:
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Calculate the Total Resistance:
- The two groups are connected in parallel. The equivalent resistance of two resistances in parallel is given by: Simplifying: Therefore:
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Calculate the Current Using Ohm's Law:
- From Ohm's law, , we can solve for the current :
Conclusion:
The current flowing through the circuit is .
Would you like any further details or have any questions?
Here are 5 related questions to expand on this topic:
- How would the total resistance change if the resistors were arranged in series instead of parallel?
- What happens to the current if the voltage is doubled but the resistance remains the same?
- How does the power dissipated by each resistor relate to the total current in the circuit?
- What is the effect on the total current if an additional parallel branch is added with four more resistors?
- How would the current change if each resistor had a resistance of instead of ?
Tip: Always remember that resistors in series add directly, while resistors in parallel follow the reciprocal addition rule!
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Math Problem Analysis
Mathematical Concepts
Ohm's Law
Series and Parallel Circuits
Equivalent Resistance
Formulas
R_{\text{series}} = R_1 + R_2 + \dots = nR
R_{\text{parallel}} = \frac{1}{R_1} + \frac{1}{R_2} + \dots
I = \frac{V}{R}
Theorems
Ohm's Law
Series and Parallel Resistance Theorem
Suitable Grade Level
Grades 10-12
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