Let's solve the problem based on the image and the text provided.

The circuit shows three resistors in series:

• $R_1 = 2 \, \Omega$
• $R_2 = 3 \, \Omega$
• $R_3 = 7 \, \Omega$

The voltage of the battery is $V = 24 \, \text{V}$.

1. Total Resistance (Hambatan Total)

In a series circuit, the total resistance $R_{\text{total}}$ is simply the sum of all the resistances:

$R_{\text{total}} = R_1 + R_2 + R_3$

$R_{\text{total}} = 2 \, \Omega + 3 \, \Omega + 7 \, \Omega = 12 \, \Omega$

2. Current (Kuat Arus)

Using Ohm's law, the current $I$ in a series circuit is given by:

$I = \frac{V}{R_{\text{total}}}$

$I = \frac{24 \, \text{V}}{12 \, \Omega} = 2 \, \text{A}$

Final Answers:

• Total resistance: $12 \, \Omega$
• Current: $2 \, \text{A}$

Would you like further details or clarifications on any part of the process?

Here are 5 related questions to consider:

1. What is the voltage drop across each resistor?
2. How would the current change if one resistor's value was altered?
3. How is total resistance calculated in parallel circuits?
4. What would happen to the current if the voltage increased to 30 V?
5. What are the differences between series and parallel circuits?

Tip: In a series circuit, the current is the same through each component, but the voltage divides according to the resistances.