Math Problem Statement

Consider the following data:

x 4 5 6 7 8 P(X=x) 0.2 0.3 0.1 0.1 0.3

Step 4 of 5 : Find the value of P(X≤5) . Round your answer to one decimal place.

Solution

To find P(X5)P(X \leq 5), we need to sum the probabilities of X=4X = 4 and X=5X = 5 from the given data.

From the data:

P(X=4)=0.2P(X = 4) = 0.2 P(X=5)=0.3P(X = 5) = 0.3

So,

P(X5)=P(X=4)+P(X=5)=0.2+0.3=0.5P(X \leq 5) = P(X = 4) + P(X = 5) = 0.2 + 0.3 = 0.5

Thus, the value of P(X5)P(X \leq 5) is 0.5.

Would you like further details or explanations on how to approach this?

Here are some related questions:

  1. How do you calculate the probability of P(X>5)P(X > 5)?
  2. What is the meaning of cumulative probability?
  3. Can you explain how to calculate the expected value of a random variable from this distribution?
  4. How does the probability distribution change if P(X=4)P(X = 4) becomes 0.4 instead of 0.2?
  5. What is the variance of a probability distribution, and how is it calculated?

Tip: When calculating cumulative probabilities like P(Xa)P(X \leq a), simply sum the probabilities for all XX values less than or equal to aa.

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Math Problem Analysis

Mathematical Concepts

Probability
Cumulative Probability
Discrete Probability Distribution

Formulas

P(X ≤ x) = Σ P(X = x) for x ≤ given value

Theorems

Cumulative Probability Theorem

Suitable Grade Level

Grades 9-11