Math Problem Statement
In cribbage, each player is dealt 6 cards from a standard deck of cards. In how many ways could a hand contain a) at least two queens
Solution
To solve the problem of determining how many hands of 6 cards in cribbage contain at least two queens, we can break it down as follows:
Step 1: Total number of hands
The total number of ways to deal a hand of 6 cards from a 52-card deck is given by:
Step 2: Find the complement ("no queens" and "exactly one queen")
Let’s use the complement rule:
- "At least two queens" is the same as not having 0 queens or 1 queen.
Step 3: Calculate hands with 0 queens
- There are 4 queens in a deck of 52 cards, so the number of cards excluding queens is 48.
- The number of hands with 0 queens is given by selecting all 6 cards from the 48 non-queen cards:
Step 4: Calculate hands with exactly 1 queen
-
We must select 1 queen out of the 4 available:
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Then we must select the remaining 5 cards from the 48 non-queen cards:
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Therefore, the number of hands with exactly 1 queen is:
Step 5: Apply the complement rule
The number of hands with at least two queens is given by:
Conclusion:
The number of hands containing at least two queens is:
Would you like further details on this or another explanation?
Here are some related questions:
- What is the probability of getting at least two queens in a cribbage hand?
- How many hands contain exactly three queens?
- How many hands contain all four queens?
- What is the probability of having no queens in a 6-card hand?
- How does this change if we deal a 5-card hand instead?
Tip: The complement rule is a powerful technique for calculating probabilities or counting cases without directly enumerating complex conditions.
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Math Problem Analysis
Mathematical Concepts
Combinatorics
Probability
Complement Rule
Formulas
\binom{n}{k} = \frac{n!}{k!(n-k)!}
Theorems
Complement Rule
Combinatorics for Card Selection
Suitable Grade Level
Grades 9-12
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