To determine how many hands contain exactly 4 kings when selecting 5 cards from a standard deck of 52 cards, we can break the problem into steps:

1. Step 1: Choose the 4 kings. There are 4 kings in a standard deck, and we need all 4 of them. The number of ways to choose 4 kings is: $\binom{4}{4} = 1$

2. Step 2: Choose 1 additional card. After removing the 4 kings, there are $52 - 4 = 48$ cards left in the deck. We need to choose 1 card from these remaining cards. The number of ways to choose 1 card is: $\binom{48}{1} = 48$

3. Step 3: Multiply the results. The total number of hands containing exactly 4 kings is the product of the ways to choose the kings and the ways to choose the additional card: $\text{Total hands} = \binom{4}{4} \cdot \binom{48}{1} = 1 \cdot 48 = 48$

Final Answer:

There are 48 hands that contain exactly 4 kings.

Would you like further clarification or examples on this? Here are some related questions:

1. How many 5-card hands contain no kings?
2. How many hands contain at least 1 king?
3. How many hands contain all 4 aces instead of kings?
4. What is the probability of drawing a hand with 4 kings in a random deal?
5. How many hands contain exactly 3 kings and 2 other cards?

Tip: Remember, a standard deck has 52 cards divided into 4 suits, with 13 cards in each suit.