Math Problem Statement
If output is produced according to π = π(πΏ,πΎ) = 4πΏπΎ, the price of K is Β£10, and the price of L is Β£40, then the cost minimizing cost minimizing combination of K and L capable of producing 64 units of output is a. πΏ = 16 πππ πΎ = 1. b. πΏ = 2 πππ πΎ = 8. c. πΏ = 2 πππ πΎ = 2. d. πΏ = 32 πππ πΎ = 32.
Solution
The production function is given by , where is the output, is labor, and is capital. The goal is to minimize the cost while producing 64 units of output, i.e., .
Step 1: Find the constraint based on the output
Since , we can set to find the constraint for and : Thus, the product of and must equal 16.
Step 2: Set up the cost function
The cost function is the total cost of labor and capital. Given that the price of (labor) is Β£40 and the price of (capital) is Β£10, the total cost is: We need to minimize this cost subject to the constraint .
Step 3: Test the options
Option a: and
- (satisfies the constraint)
- Cost:
Option b: and
- (satisfies the constraint)
- Cost:
Option c: and
- (does not satisfy the constraint)
Option d: and
- (does not satisfy the constraint)
Conclusion:
The cost-minimizing combination that satisfies the constraint is Option b: and , with a cost of Β£160.
Would you like more details or have any questions? Here are some relative questions for further practice:
- How do you derive the cost function in production problems?
- What is the method to minimize cost when given a production function?
- How would the cost change if the price of were Β£20 instead of Β£10?
- What is the importance of the marginal product of labor and capital in production?
- How does changing the production function affect the optimal labor-capital combination?
Tip: Always verify that the solution satisfies the production constraint before checking the cost.
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Math Problem Analysis
Mathematical Concepts
Algebra
Optimization
Cost Minimization
Production Functions
Formulas
Production function: Y = f(L, K) = 4LK
Cost function: C = 40L + 10K
Output constraint: LK = 16
Theorems
Cost minimization under a production constraint
Lagrange multiplier method for optimization (optional)
Suitable Grade Level
Grades 10-12
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