Math Problem Statement

Question content area top Part 1 A truck can be rented from Company A for ​$80 a day plus ​$0.40 per mile. Company B charges ​$50 a day plus ​$0.70 per mile to rent the same truck. Find the number of miles in a day at which the rental costs for Company A and Company B are the same

Solution

Let's solve for the number of miles, xx, at which the daily rental costs for Company A and Company B are equal.

Step 1: Set up the cost equations

Let xx represent the number of miles driven in a day.

  1. Cost for Company A: CostA=80+0.40x\text{Cost}_{A} = 80 + 0.40x

  2. Cost for Company B: CostB=50+0.70x\text{Cost}_{B} = 50 + 0.70x

Step 2: Set the equations equal to each other

To find when the costs are the same, set the two equations equal to each other: 80+0.40x=50+0.70x80 + 0.40x = 50 + 0.70x

Step 3: Solve for xx

  1. Subtract 0.40x0.40x from both sides: 80=50+0.30x80 = 50 + 0.30x

  2. Subtract 50 from both sides: 30=0.30x30 = 0.30x

  3. Divide by 0.30 to isolate xx: x=300.30=100x = \frac{30}{0.30} = 100

Conclusion

The number of miles at which the rental costs for Company A and Company B are the same is 100 miles.

Would you like further clarification on any part of this process?


Here are some additional related questions for practice:

  1. What would the cost be for each company if 100 miles were driven?
  2. How would the cost comparison change if Company A increased its daily charge?
  3. How many miles would need to be driven for Company B to be the cheaper option?
  4. If Company B charged $0.50 per mile, at what point would the costs be equal?
  5. What if Company A charged $100 per day and $0.30 per mile?

Tip: Setting up equations is crucial for solving comparison problems effectively.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Cost Comparison

Formulas

Cost = fixed cost + (cost per mile * miles)

Theorems

Equation solving for equality

Suitable Grade Level

Grades 7-9