To solve the equation $3x - 4y = 16$ for $y$ in slope-intercept form ($y = mx + b$), follow these steps:

1. Start with the equation: $3x - 4y = 16$

2. Isolate the term with $y$ by subtracting $3x$ from both sides: $-4y = -3x + 16$

3. Divide every term by $-4$ to solve for $y$: $y = \frac{-3x + 16}{-4}$

4. Simplify the equation: $y = \frac{3}{4}x - 4$

So, the equation in slope-intercept form is:

$y = \frac{3}{4}x - 4$

Here, the slope $m$ is $\frac{3}{4}$ and the y-intercept $b$ is $-4$.

Would you like a detailed explanation of any of these steps, or do you have any other questions?

Here are some related questions you might find useful:

1. How do you find the slope of a line given two points?
2. What is the significance of the slope and y-intercept in a linear equation?
3. How do you convert from slope-intercept form to standard form?
4. How can you graph a line given its slope-intercept form?
5. What are parallel and perpendicular slopes?

Tip: When converting equations, always try to simplify the fraction to make the slope easier to interpret!