Math Problem Statement

Convert the second-order system of ODEs describing the two-mass/three-spring problem into a linear system of four first-order ODEs.

Solution

The problem involves converting the given second-order system of ordinary differential equations (ODEs) into a system of four first-order ODEs. Let’s break it down step-by-step.

The second-order equations are: m1d2x1dt2=(k1+k2)x1+k2x2,m_1 \frac{d^2x_1}{dt^2} = -(k_1 + k_2)x_1 + k_2x_2, m2d2x2dt2=k2x1(k2+k3)x2.m_2 \frac{d^2x_2}{dt^2} = k_2x_1 - (k_2 + k_3)x_2.

The values provided are: m1=1,m2=32,k1=32,k2=2,k3=1.m_1 = 1, \quad m_2 = \frac{3}{2}, \quad k_1 = \frac{3}{2}, \quad k_2 = 2, \quad k_3 = 1.

To convert this into a first-order system, we define the variables: u1=x1,u2=x2,u3=dx1dt,u4=dx2dt.u_1 = x_1, \quad u_2 = x_2, \quad u_3 = \frac{dx_1}{dt}, \quad u_4 = \frac{dx_2}{dt}.

Step 1: Substituting variables

Rewrite the original equations using the new variables. For the second derivatives: d2x1dt2=du3dt,d2x2dt2=du4dt.\frac{d^2x_1}{dt^2} = \frac{du_3}{dt}, \quad \frac{d^2x_2}{dt^2} = \frac{du_4}{dt}.

Using the first-order variables, we form the following system:

  1. du1dt=u3\frac{du_1}{dt} = u_3,
  2. du2dt=u4\frac{du_2}{dt} = u_4,
  3. From the first equation: m1du3dt=(k1+k2)u1+k2u2,m_1 \frac{du_3}{dt} = -(k_1 + k_2)u_1 + k_2u_2, which simplifies to: du3dt=(k1+k2)m1u1+k2m1u2.\frac{du_3}{dt} = \frac{-(k_1 + k_2)}{m_1}u_1 + \frac{k_2}{m_1}u_2.
  4. From the second equation: m2du4dt=k2u1(k2+k3)u2,m_2 \frac{du_4}{dt} = k_2u_1 - (k_2 + k_3)u_2, which simplifies to: du4dt=k2m2u1(k2+k3)m2u2.\frac{du_4}{dt} = \frac{k_2}{m_2}u_1 - \frac{(k_2 + k_3)}{m_2}u_2.

Step 2: Substituting parameter values

Substitute m1=1m_1 = 1, m2=32m_2 = \frac{3}{2}, k1=32k_1 = \frac{3}{2}, k2=2k_2 = 2, k3=1k_3 = 1 into the system:

  1. du1dt=u3\frac{du_1}{dt} = u_3,
  2. du2dt=u4\frac{du_2}{dt} = u_4,
  3. du3dt=(32+21)u1+21u2=72u1+2u2\frac{du_3}{dt} = -\left(\frac{\frac{3}{2} + 2}{1}\right)u_1 + \frac{2}{1}u_2 = -\frac{7}{2}u_1 + 2u_2,
  4. du4dt=232u1(2+1)32u2=43u12u2\frac{du_4}{dt} = \frac{2}{\frac{3}{2}}u_1 - \frac{(2 + 1)}{\frac{3}{2}}u_2 = \frac{4}{3}u_1 - 2u_2.

Step 3: Final system

The system of four first-order ODEs is: du1dt=u3,\frac{du_1}{dt} = u_3, du2dt=u4,\frac{du_2}{dt} = u_4, du3dt=72u1+2u2,\frac{du_3}{dt} = -\frac{7}{2}u_1 + 2u_2, du4dt=43u12u2.\frac{du_4}{dt} = \frac{4}{3}u_1 - 2u_2.

Let me know if you’d like further clarifications or help visualizing this!


Questions for Further Exploration:

  1. How can the system matrix AA for u=Au\mathbf{u}' = A\mathbf{u} be derived from the above system?
  2. What are the eigenvalues of the matrix AA, and what do they signify physically?
  3. How would the system change if external forcing terms F1(t)F_1(t) and F2(t)F_2(t) were included?
  4. Can this system be solved explicitly, and if so, what are the solutions?
  5. How does changing one of the spring constants (e.g., k3k_3) affect the system's dynamics?

Tip:

When converting second-order systems to first-order, always clearly define your substitution variables to avoid confusion in subsequent steps.

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Math Problem Analysis

Mathematical Concepts

Ordinary Differential Equations
Linear Systems

Formulas

m1 * d^2x1/dt^2 = -(k1 + k2)x1 + k2x2
m2 * d^2x2/dt^2 = k2x1 - (k2 + k3)x2

Theorems

System of First-Order Linear ODEs

Suitable Grade Level

Undergraduate Engineering or Physics