Math Problem Statement

A point is graphed in polar form. Find its rectangular coordinates.

Solution

To find the rectangular coordinates (x,y)(x, y) from the polar coordinates given, use the following formulas:

x=rcosθx = r \cos \theta y=rsinθy = r \sin \theta

From the image:

  • r=2r = 2
  • θ=5π6\theta = \frac{5\pi}{6}

Now calculate:

  1. xx: x=2cos(5π6)x = 2 \cos\left(\frac{5\pi}{6}\right) The cosine of 5π6\frac{5\pi}{6} is 32-\frac{\sqrt{3}}{2}. So, x=2×32=3.x = 2 \times -\frac{\sqrt{3}}{2} = -\sqrt{3}.

  2. yy: y=2sin(5π6)y = 2 \sin\left(\frac{5\pi}{6}\right) The sine of 5π6\frac{5\pi}{6} is 12\frac{1}{2}. So, y=2×12=1.y = 2 \times \frac{1}{2} = 1.

Thus, the rectangular coordinates are: (x,y)=(3,1).(x, y) = (-\sqrt{3}, 1).

Would you like a detailed explanation or assistance with related concepts?

Here are five related questions to explore:

  1. How are polar and rectangular coordinates used in real-world applications?
  2. Can polar coordinates be converted to rectangular coordinates if θ\theta is negative?
  3. What are the reverse formulas to convert rectangular to polar coordinates?
  4. How can you interpret angles like 5π6\frac{5\pi}{6} geometrically?
  5. What are the key differences between polar and rectangular coordinate systems?

Tip: Always

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Math Problem Analysis

Mathematical Concepts

Polar Coordinates
Rectangular Coordinates
Trigonometric Functions

Formulas

x = r * cos(θ)
y = r * sin(θ)

Theorems

Trigonometric Properties of Sine and Cosine

Suitable Grade Level

Grades 9-12