Math Problem Statement

Dans chacun des cas suivants, étudier la continuité de la fonction f au point x_0.

Solution

The image presents a set of mathematical problems focused on the continuity of functions at specific points. Here's a breakdown of what the tasks ask for:

  1. First question: Continuity study for different functions at given points:

    You are asked to determine the continuity of several functions at specified points x0x_0.

    • a) f(x)=2x2x+1x+1f(x) = \frac{-2x^2 - x + 1}{x + 1} for x1x \neq -1, with x0=1x_0 = -1, and f(1)=1f(-1) = 1.
    • b) f(x)=x+tan(2x)sin(3x)f(x) = \frac{x + \tan(2x)}{\sin(3x)} for x0x \neq 0, with x0=0x_0 = 0, and f(0)=1f(0) = 1.
    • c) f(x)=x2+x+22x1f(x) = \frac{\sqrt{x^2 + x + 2} - 2}{x - 1} for x1x \neq 1, with x0=1x_0 = 1, and f(1)=34f(1) = \frac{3}{4}.
    • d) f(x)=sin(x)x+11f(x) = \frac{\sin(x)}{\sqrt{x+1} - 1} for x0x \neq 0, with x0=0x_0 = 0, and f(0)=2f(0) = 2.

    For each part, you need to:

    • Determine the limit of the function as xx approaches the given point x0x_0.
    • Compare this limit to the value of the function at the point (if it exists) to verify if the function is continuous.
  2. Second question: Continuity of function g(x)g(x) at x0=2x_0 = 2

    You are asked to find the value of λ\lambda such that the function g(x)=x32x2x+2x24g(x) = \frac{x^3 - 2x^2 - x + 2}{x^2 - 4}, with g(2)=λg(2) = \lambda, is continuous at x0=2x_0 = 2.

Would you like me to walk you through the detailed solutions for each part of the question? Let me know if you'd like to start with a specific part or if you have a question on continuity.

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Math Problem Analysis

Mathematical Concepts

Continuity of functions
Limits
Algebraic functions
Trigonometric functions
Piecewise functions

Formulas

Limit as x approaches a point (lim x->x0 f(x))
Function continuity: f(x0) = lim x->x0 f(x)
Algebraic simplification
Trigonometric limit properties

Theorems

Definition of continuity
Squeeze theorem
Trigonometric limits theorem

Suitable Grade Level

Grades 11-12 (Pre-Calculus/Calculus level)