Math Problem Statement

The data represent the time, in minutes, spent reading a political blog in a day. Construct a frequency distribution using 5 classes. In the table, include the midpoints, relative frequencies, and cumulative frequencies.

(1 29 23 14) (14 10 27 16) (13 21 27 24) (17 20 16 0) (23 22 18 12)

Fill in the blanks, starting with the lowest class limit.

Class = _ to _ Frequency = _ Midpoint = _ Relative frequency = _ Cumulative frequency = _

Solution

To construct a frequency distribution with 5 classes, let's break down the process step by step.

1. Data Overview

The data points are: 1, 29, 23, 14, 14, 10, 27, 16, 13, 21, 27, 24, 17, 20, 16, 0, 23, 22, 18, 12

2. Range of Data

  • Minimum value: 0
  • Maximum value: 29

3. Class Width Calculation

To determine the class width, we can use the formula: Class Width=RangeNumber of Classes\text{Class Width} = \frac{\text{Range}}{\text{Number of Classes}} Class Width=2905=2955.86 (rounded up to nearest whole number)\text{Class Width} = \frac{29 - 0}{5} = \frac{29}{5} \approx 5.8 \approx 6 \text{ (rounded up to nearest whole number)}

4. Class Limits and Frequency Distribution

Now, we define the 5 classes, calculate frequencies, midpoints, relative frequencies, and cumulative frequencies.

Class 1:

  • Class = 0 to 5
  • Frequency = 2 (Data points: 0, 1)
  • Midpoint = 0+52=2.5\frac{0 + 5}{2} = 2.5
  • Relative Frequency = 220=0.10\frac{2}{20} = 0.10
  • Cumulative Frequency = 2

Class 2:

  • Class = 6 to 11
  • Frequency = 3 (Data points: 10, 12, 10)
  • Midpoint = 6+112=8.5\frac{6 + 11}{2} = 8.5
  • Relative Frequency = 320=0.15\frac{3}{20} = 0.15
  • Cumulative Frequency = 2 + 3 = 5

Class 3:

  • Class = 12 to 17
  • Frequency = 8 (Data points: 14, 14, 16, 13, 16, 17, 12)
  • Midpoint = 12+172=14.5\frac{12 + 17}{2} = 14.5
  • Relative Frequency = 820=0.40\frac{8}{20} = 0.40
  • Cumulative Frequency = 5 + 8 = 13

Class 4:

  • Class = 18 to 23
  • Frequency = 6 (Data points: 18, 20, 21, 22, 23, 23)
  • Midpoint = 18+232=20.5\frac{18 + 23}{2} = 20.5
  • Relative Frequency = 620=0.30\frac{6}{20} = 0.30
  • Cumulative Frequency = 13 + 6 = 19

Class 5:

  • Class = 24 to 29
  • Frequency = 4 (Data points: 24, 27, 27, 29)
  • Midpoint = 24+292=26.5\frac{24 + 29}{2} = 26.5
  • Relative Frequency = 420=0.20\frac{4}{20} = 0.20
  • Cumulative Frequency = 19 + 4 = 20

Summary Table

ClassFrequencyMidpointRelative FrequencyCumulative Frequency
0 to 522.50.102
6 to 1138.50.155
12 to 17814.50.4013
18 to 23620.50.3019
24 to 29426.50.2020

Would you like more details or have any questions?


Here are 5 related questions:

  1. How would the frequency distribution change if the data included a new entry of 30?
  2. Can you calculate the cumulative relative frequency for each class?
  3. What would the distribution look like if we used 6 classes instead of 5?
  4. How does the midpoint help in understanding the frequency distribution?
  5. What is the significance of the relative frequency in interpreting the data?

Tip: Always ensure that the sum of the relative frequencies equals 1, as it represents the entire dataset.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Statistics
Frequency distribution
Class intervals
Relative frequency
Cumulative frequency

Formulas

Class width calculation: \( \text{Class Width} = \frac{\text{Range}}{\text{Number of Classes}} \)

Theorems

-

Suitable Grade Level

High School