Math Problem Statement

Step 3 of 3 :

Construct the 90%

confidence interval. Round your answers to three decimal places.

Solution

To construct a 90% confidence interval, you'll typically need the following information:

  1. The sample mean (xˉ\bar{x})
  2. The standard deviation (ss) or population standard deviation (σ\sigma), if available
  3. The sample size (nn)
  4. The confidence level (which is 90% in this case)

Formula for a confidence interval for the mean:

If you're dealing with a sample and the population standard deviation is unknown, use the t-distribution:

CI=xˉ±tα/2sn\text{CI} = \bar{x} \pm t_{\alpha/2} \cdot \frac{s}{\sqrt{n}}

Where:

  • xˉ\bar{x} is the sample mean
  • ss is the sample standard deviation
  • nn is the sample size
  • tα/2t_{\alpha/2} is the critical value from the t-distribution for a 90% confidence level and n1n - 1 degrees of freedom

If the population standard deviation (σ\sigma) is known, use the z-distribution:

CI=xˉ±zα/2σn\text{CI} = \bar{x} \pm z_{\alpha/2} \cdot \frac{\sigma}{\sqrt{n}}

Where zα/2z_{\alpha/2} is the critical value from the standard normal distribution for a 90% confidence level.

Steps to calculate:

  1. Find the sample mean (xˉ\bar{x}).
  2. Determine the standard deviation (ss or σ\sigma).
  3. Find the appropriate critical value (tα/2t_{\alpha/2} or zα/2z_{\alpha/2}).
    • For a 90% confidence level, the critical value zα/2z_{\alpha/2} from the z-distribution is approximately 1.645.
    • If using the t-distribution, look up the t-value based on your sample size.
  4. Calculate the margin of error: tα/2snt_{\alpha/2} \cdot \frac{s}{\sqrt{n}} or zα/2σnz_{\alpha/2} \cdot \frac{\sigma}{\sqrt{n}}.
  5. Construct the confidence interval by adding and subtracting the margin of error from the sample mean.

Please provide the sample mean, standard deviation, and sample size (if known), so I can assist you in calculating the confidence interval.


Do you have these details, or would you like further clarification on any step?


Related Questions:

  1. What happens to the width of the confidence interval as the confidence level increases?
  2. How does the sample size affect the margin of error in a confidence interval?
  3. Why is the t-distribution used when the population standard deviation is unknown?
  4. How do we determine the appropriate critical value for a confidence interval?
  5. What role does variability in data play in constructing confidence intervals?

Tip: Increasing your sample size reduces the margin of error, leading to a narrower confidence interval.

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Math Problem Analysis

Mathematical Concepts

Statistics
Confidence Interval
Probability

Formulas

CI = \bar{x} \pm z_{\alpha/2} \cdot \frac{\sigma}{\sqrt{n}}
CI = \bar{x} \pm t_{\alpha/2} \cdot \frac{s}{\sqrt{n}}

Theorems

Central Limit Theorem
t-distribution
z-distribution

Suitable Grade Level

Undergraduate/College Level