The given function is:

$f(x) = 3 + \sqrt{2} - 1$

This appears to be a constant function, meaning that for any value of $x$, the output $f(x)$ will always be the same.

Simplifying the expression:

$f(x) = 3 - 1 + \sqrt{2} = 2 + \sqrt{2}$

So, the function becomes:

$f(x) = 2 + \sqrt{2}$

This implies that:

• The graph of $f(x)$ is a horizontal line at $y = 2 + \sqrt{2}$.
• The domain of $f(x)$ is all real numbers ($-\infty, \infty$).
• The range of $f(x)$ is a single value: $\{2 + \sqrt{2}\}$.

Would you like me to expand on this further, such as graphing the function or discussing its properties in more detail?

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Here are 5 related questions you may explore:

1. How do you graph a constant function like $f(x) = 2 + \sqrt{2}$?
2. What is the domain and range of a constant function?
3. How does $f(x) = c$ behave when included in equations or inequalities?
4. Can you apply transformations to a constant function?
5. How does the value of $\sqrt{2}$ influence the constant $f(x)$?

Tip: When working with constant functions, remember that their derivatives are always zero, as there is no change in $y$ with respect to $x$.