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The image you uploaded shows a geometry problem that appears to involve comparing two triangles. Here’s a breakdown of what the image contains:

### Problem Statement:
- **Given:**
  - \(\triangle ABC\) with sides \(AB = 6\), \(BC = 8\), and \(AC = 10\).
  - Another triangle \(\triangle DEF\) with the same dimensions as \(\triangle ABC\).

- **Task:**
  - Compare \(\triangle ABC\) and \(\triangle DEF\).
  
### Observation:
- The triangles \(\triangle ABC\) and \(\triangle DEF\) are right-angled triangles. This is because the side lengths given (6, 8, and 10) satisfy the Pythagorean theorem (\(6^2 + 8^2 = 10^2\)), which confirms that they are right triangles.

### Comparison:
- **Congruence:** Since both triangles have the same side lengths (6, 8, and 10), they are congruent by the SSS (Side-Side-Side) congruence criterion.
  
Would you like a detailed explanation of congruence and similarity of triangles or any further assistance?

Here are 5 related questions:
1. What are the different criteria for triangle congruence?
2. How do you prove that two triangles are similar?
3. Can congruent triangles have different angles?
4. How do the properties of right triangles apply in real-world situations?
5. What is the significance of the Pythagorean theorem in geometry?

**Tip:** Remember that congruent triangles have identical angles and side lengths, which makes them perfect overlays of each other.

Compare triangles ABC and DEF, where triangle ABC has sides AB = 6, BC = 8, and AC = 10, and triangle DEF has the same dimensions.

Understand the congruence of right triangles ABC and DEF, each with sides 6, 8, and 10. This problem uses the SSS Congruence Theorem and the Pythagorean theorem to demonstrate triangle congruence. Suitable for students in Grades 8-10.

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