Since events $A$ and $B$ are independent, the probability of $A$ given $B$ is equal to the probability of $A$. This is because, in independent events, knowing that $B$ has occurred does not change the likelihood of $A$ occurring.

So, for independent events:

$P(A \mid B) = P(A)$

Given that $P(A) = 0.55$, we conclude:

$P(A \mid B) = 0.55$

Would you like more details or have any other questions on this?

Here are 5 related questions to consider:

1. How would you find $P(B \mid A)$?
2. What is the formula for the probability of the intersection of two independent events?
3. How do you calculate $P(A \cup B)$ for independent events?
4. If $P(A \cap B) = P(A) \times P(B)$, what is the intersection probability here?
5. What changes if events $A$ and $B$ are dependent instead of independent?

Tip: Independence implies that the occurrence of one event does not affect the probability of the other event.