Math Problem Statement

Suppose that (X1, X2) has the centered normal distribution with density (29.10). Express the quadratic form in the exponential and integrate out x2 to show the conditional distribution of X2 given X1.

Solution

To solve this problem, let's break down the steps in detail.

Step 1: Understanding the Quadratic Form in the Exponential

We start with the centered normal distribution for (X1,X2)(X_1, X_2), with density defined in the form given by equation (29.10), where the exponential has a quadratic form. We're asked to express the quadratic form as: 1σ11x12+σ11D(x2σ12σ11x1)2\frac{1}{\sigma_{11}} x_1^2 + \frac{\sigma_{11}}{D} \left( x_2 - \frac{\sigma_{12}}{\sigma_{11}} x_1 \right)^2

This expression likely comes from transforming the joint distribution of (X1,X2)(X_1, X_2) into a form that separates the contributions of x1x_1 and x2x_2, making it easier to isolate and integrate out x2x_2.

Step 2: Integrate Out x2x_2

We want to integrate x2x_2 out from the joint density function f(x1,x2)f(x_1, x_2) to obtain the marginal distribution of X1X_1. The problem states: f(x1,x2)=12πτexp[12τ(x2σ12σ11x1)2]f(x_1, x_2) = \frac{1}{\sqrt{2 \pi \tau}} \exp\left[ -\frac{1}{2\tau} \left( x_2 - \frac{\sigma_{12}}{\sigma_{11}} x_1 \right)^2 \right] where τ=σ22σ122σ111\tau = \sigma_{22} - \sigma_{12}^2 \sigma_{11}^{-1}.

The integral to perform here is: f(x1,t)dt\int_{-\infty}^{\infty} f(x_1, t) \, dt This integral would give us the conditional distribution of X2X_2 given X1X_1.

Step 3: Describe the Conditional Distribution of X2X_2 Given X1X_1

The form of the exponential term suggests that X2X1X_2 | X_1 is normally distributed with mean: E[X2X1]=σ12σ11x1\mathbb{E}[X_2 | X_1] = \frac{\sigma_{12}}{\sigma_{11}} x_1 and variance: Var(X2X1)=τ=σ22σ122σ11\text{Var}(X_2 | X_1) = \tau = \sigma_{22} - \frac{\sigma_{12}^2}{\sigma_{11}}

Thus, the conditional distribution of X2X_2 given X1X_1 is: X2X1N(σ12σ11X1,σ22σ122σ11)X_2 | X_1 \sim \mathcal{N} \left( \frac{\sigma_{12}}{\sigma_{11}} X_1, \sigma_{22} - \frac{\sigma_{12}^2}{\sigma_{11}} \right)

Would you like further details on any specific step?

Follow-up Questions

  1. How is the covariance matrix used to define the joint distribution of two normal variables?
  2. How do we derive conditional distributions from joint normal distributions?
  3. What is the role of the determinant DD in normal distribution problems?
  4. Why is integrating out a variable useful in probability density functions?
  5. How does the value of σ12\sigma_{12} affect the relationship between X1X_1 and X2X_2?

Tip: When working with conditional distributions in multivariate normals, remember that conditioning often reduces the variance, as seen here with τ\tau.

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Math Problem Analysis

Mathematical Concepts

Multivariate Normal Distribution
Conditional Probability
Integration

Formulas

Quadratic form in normal distribution: (1/σ11) x1^2 + (σ11/D) (x2 - (σ12/σ11) x1)^2
Conditional density: f(x1, x2) = (1 / √(2πτ)) exp[-(1 / (2τ)) (x2 - (σ12/σ11) x1)^2]
τ = σ22 - σ12^2/σ11

Theorems

Conditional Distribution of Multivariate Normal
Properties of Gaussian Integrals

Suitable Grade Level

Undergraduate