Math Problem Statement
Solution
To solve this problem, let's break down the steps in detail.
Step 1: Understanding the Quadratic Form in the Exponential
We start with the centered normal distribution for , with density defined in the form given by equation (29.10), where the exponential has a quadratic form. We're asked to express the quadratic form as:
This expression likely comes from transforming the joint distribution of into a form that separates the contributions of and , making it easier to isolate and integrate out .
Step 2: Integrate Out
We want to integrate out from the joint density function to obtain the marginal distribution of . The problem states: where .
The integral to perform here is: This integral would give us the conditional distribution of given .
Step 3: Describe the Conditional Distribution of Given
The form of the exponential term suggests that is normally distributed with mean: and variance:
Thus, the conditional distribution of given is:
Would you like further details on any specific step?
Follow-up Questions
- How is the covariance matrix used to define the joint distribution of two normal variables?
- How do we derive conditional distributions from joint normal distributions?
- What is the role of the determinant in normal distribution problems?
- Why is integrating out a variable useful in probability density functions?
- How does the value of affect the relationship between and ?
Tip: When working with conditional distributions in multivariate normals, remember that conditioning often reduces the variance, as seen here with .
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Math Problem Analysis
Mathematical Concepts
Multivariate Normal Distribution
Conditional Probability
Integration
Formulas
Quadratic form in normal distribution: (1/σ11) x1^2 + (σ11/D) (x2 - (σ12/σ11) x1)^2
Conditional density: f(x1, x2) = (1 / √(2πτ)) exp[-(1 / (2τ)) (x2 - (σ12/σ11) x1)^2]
τ = σ22 - σ12^2/σ11
Theorems
Conditional Distribution of Multivariate Normal
Properties of Gaussian Integrals
Suitable Grade Level
Undergraduate
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