Math Problem Statement

kan je oefening 3 oplossen?

kan je oefening 3 oplossen?

Solution

Yes, let’s analyze and solve exercise 3 based on the information provided in the uploaded image.

Problem Analysis:

For the function f(x)=xex2f(x) = x e^{x^2}, we are tasked to:

  1. Determine the intervals where the function is concave or convex.
  2. Identify the inflection points (buigpunten).

Solution Steps:

Step 1: Find the first derivative f(x)f'(x)

Using the product rule and chain rule for differentiation, we get: f(x)=xex2f(x) = x \cdot e^{x^2} f(x)=ex2(2x2+1)f'(x) = e^{x^2} \cdot (2x^2 + 1)

Step 2: Find the second derivative f(x)f''(x)

To determine concavity, we need the second derivative: f(x)=2xex2(2x2+3)f''(x) = 2x \cdot e^{x^2} \cdot (2x^2 + 3)

Step 3: Analyze concavity

  1. The function is concave (downwards) when f(x)<0f''(x) < 0. This occurs when x<0x < 0.
  2. The function is convex (upwards) when f(x)>0f''(x) > 0. This occurs when x>0x > 0.

Step 4: Identify inflection points

An inflection point occurs where the concavity changes, which means at x=0x = 0 (since the function changes from concave to convex here).

Thus, the function has an inflection point at (0,0)(0, 0).

Summary:

  • The function f(x)=xex2f(x) = x e^{x^2} is concave for x<0x < 0 and convex for x>0x > 0.
  • There is an inflection point at (0,0)(0, 0).

Would you like further details on any step, or do you have specific questions about the solution?

Here are five related questions you might consider:

  1. How can the product rule be applied in other contexts?
  2. What are common methods to verify inflection points?
  3. How does convexity relate to real-world applications?
  4. Can higher derivatives provide insights into the behavior of functions?
  5. How would the solution change if the function had additional terms?

Tip: Understanding concavity and convexity can help in sketching graphs and analyzing the behavior of functions over different intervals.

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Math Problem Analysis

Mathematical Concepts

Calculus
Concavity and Convexity
Inflection Points

Formulas

Product rule for differentiation: (uv)' = u'v + uv'
Chain rule for differentiation
Second derivative for concavity analysis

Theorems

Concavity and convexity criteria based on second derivative

Suitable Grade Level

Grades 11-12