Math Problem Statement
Given that the acceleration vector is a(t)=(-9cos(3t))I+(-9sin(3t))J+(3t)K , the initial velocity is v(0)=I+K , and the initial position vector is X(0)=I+J+K , compute: The velocity vector and position vector
Solution
To compute the velocity vector and position vector , we need to integrate the acceleration vector with respect to time , using the initial conditions provided.
Given:
- Initial velocity
- Initial position
Step 1: Compute the velocity vector
The velocity vector is obtained by integrating the acceleration vector:
We integrate each component of :
Now, we use the initial condition , which gives:
- , so
- , so
- , so
Thus, the velocity vector becomes:
Step 2: Compute the position vector
The position vector is obtained by integrating the velocity vector:
We integrate each component of :
Now, we use the initial condition , which gives:
- , so
- , so
- , so
Thus, the position vector becomes:
Final Answer:
-
Velocity vector:
-
Position vector:
Would you like more details on any of these steps, or do you have any questions?
Related questions:
- How would the problem change if the initial velocity were different?
- What is the physical interpretation of the cosine and sine functions in the velocity?
- How would you find the time when the particle returns to its initial position?
- What is the speed of the particle as a function of time?
- How does the velocity change for large values of ?
Tip: To find the total distance traveled by the particle, you need to integrate the speed over time, which is the magnitude of the velocity vector.
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Math Problem Analysis
Mathematical Concepts
Vector Calculus
Kinematics
Integration
Formulas
Velocity vector: v(t) = ∫ a(t) dt
Position vector: X(t) = ∫ v(t) dt
Theorems
Fundamental Theorem of Calculus
Suitable Grade Level
Undergraduate (Calculus-based Physics)
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