Math Problem Statement
Solution
To solve this problem, we need to compute the integral
where the graph of is given. The area under this curve, bounded between and , represents the integral. From the graph, we can see that the curve is composed of two distinct sections:
- A straight line from to .
- A semicircle with a radius of 4 centered at and spanning from to .
We will calculate the area under each section separately.
Step 1: Area under the Line Segment from to
The line segment from to has a triangular shape. It starts at the point and rises linearly to . The area of this triangle can be calculated as:
Step 2: Area under the Semicircle from to
The semicircle extends horizontally from to with a radius of 4, centered at . The area of a full circle with radius would be:
Since we only need the area of the upper half (a semicircle), we take half of this value:
Step 3: Total Area under from to
Adding the areas from the line segment and the semicircle gives:
Final Answer
The exact answer to the integral is:
Would you like further details or have any questions?
Follow-Up Questions
- How would the answer change if the semicircle were below the -axis?
- What would happen if we integrated from to ?
- How do we interpret the integral geometrically if the function changes below and above the -axis?
- How would we approach this if the curve included multiple semicircles?
- What is the importance of symmetry in calculating areas for shapes like semicircles?
Tip
When interpreting areas under curves for integrals, splitting the region based on shapes (like triangles and semicircles) often simplifies the calculation.
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Math Problem Analysis
Mathematical Concepts
Integration
Area under a curve
Semicircles
Triangles
Formulas
Area of a triangle = \( \frac{1}{2} \times \text{base} \times \text{height} \)
Area of a circle = \( \pi r^2 \)
Integral of \( f(x) \) from \( a \) to \( b \) represents area under the curve
Theorems
Definite Integral as Area
Suitable Grade Level
University Level - Calculus I
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