Math Problem Statement

If you invest $10,000 at an interest rate of 5.2%, determine the total amount after 5 years at the indicated compounding options. Show all work. a. Compounded Annually b. Compounded Monthly c. Compounded Daily d. Compounded Continuously

Solution

To solve these problems, we will use the following formulas for each compounding option:

  1. Compounded Annually, Monthly, and Daily:
    The formula is: A=P(1+rn)ntA = P \left(1 + \frac{r}{n}\right)^{nt} where:

    • AA is the amount after time tt,
    • PP is the principal (initial amount, here $10,000),
    • rr is the annual interest rate (5.2% or 0.052),
    • nn is the number of times the interest is compounded per year (1 for annually, 12 for monthly, 365 for daily),
    • tt is the number of years (5 years in this case).
  2. Compounded Continuously: The formula is: A=PertA = P \cdot e^{rt} where ee is the base of the natural logarithm (approximately 2.71828).

Let’s go through each option:

a. Compounded Annually (n=1n = 1)

A=10000(1+0.0521)1×5A = 10000 \left(1 + \frac{0.052}{1}\right)^{1 \times 5} A=10000×(1.052)5A = 10000 \times (1.052)^5 Calculating this gives: A10000×1.288268A \approx 10000 \times 1.288268 A12882.68A \approx 12882.68

b. Compounded Monthly (n=12n = 12)

A=10000(1+0.05212)12×5A = 10000 \left(1 + \frac{0.052}{12}\right)^{12 \times 5} A=10000×(1+0.0043333)60A = 10000 \times \left(1 + 0.0043333\right)^{60} A10000×1.289961A \approx 10000 \times 1.289961 A12899.61A \approx 12899.61

c. Compounded Daily (n=365n = 365)

A=10000(1+0.052365)365×5A = 10000 \left(1 + \frac{0.052}{365}\right)^{365 \times 5} A=10000×(1+0.0001424658)1825A = 10000 \times \left(1 + 0.0001424658\right)^{1825} A10000×1.290429A \approx 10000 \times 1.290429 A12904.29A \approx 12904.29

d. Compounded Continuously

A=10000e0.052×5A = 10000 \cdot e^{0.052 \times 5} A=10000e0.26A = 10000 \cdot e^{0.26} Calculating e0.261.29693e^{0.26} \approx 1.29693: A10000×1.29693A \approx 10000 \times 1.29693 A12969.30A \approx 12969.30

Summary

  • Compounded Annually: $12,882.68
  • Compounded Monthly: $12,899.61
  • Compounded Daily: $12,904.29
  • Compounded Continuously: $12,969.30

Would you like a breakdown of each calculation step?


Related Questions:

  1. What happens to the final amount if the interest rate increases to 6%?
  2. How does changing the compounding period affect the growth rate?
  3. What would the final amount be if invested for 10 years instead of 5?
  4. How is continuous compounding derived mathematically from discrete compounding?
  5. What if the interest rate were compounded quarterly instead of monthly?

Tip: Continuous compounding often results in the highest yield due to the nature of exponential growth with no interval between compounding

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Math Problem Analysis

Mathematical Concepts

Interest Calculation
Compound Interest
Exponential Growth
Continuous Compounding

Formulas

A = P * (1 + r/n)^(nt) for compounded annually, monthly, and daily
A = P * e^(rt) for compounded continuously

Theorems

Compound Interest Theorem
Exponential Growth Theorem

Suitable Grade Level

Grades 9-11