$$ fx=\sqrt{3x-5} $$. $$ hx=2x^2. $$ $$ \left(f\theta f\right) $$($$  $$$$ x) $$

To clarify, it seems you're asking to evaluate the composition of functions $ f $ and $ h $, possibly in terms of $(f \circ f)(x)$ (i.e., applying $ f $ to itself), but the notation in your query is a bit ambiguous.

Let’s break down what you’ve provided and solve for different possibilities:

### Definitions:
1. $ f(x) = \sqrt{3x - 5} $
2. $ h(x) = 2x^2 $
3. You’ve written "fθf", which I'll interpret as $ (f \circ f)(x) $ (the composition of $ f $ with itself).

### Finding $ (f \circ f)(x) $:

The composition of $ f(x) $ with itself means applying $ f $ to $ f(x) $, or:

\[
(f \circ f)(x) = f(f(x))
\]

First, substitute $ f(x) = \sqrt{3x - 5} $ into itself:

\[
f(f(x)) = f\left(\sqrt{3x - 5}\right)
\]

Now apply the definition of $ f(x) $ to this new input:

\[
f\left(\sqrt{3x - 5}\right) = \sqrt{3\left(\sqrt{3x - 5}\right) - 5}
\]

Simplify the inner expression:

\[
3\left(\sqrt{3x - 5}\right) = 3^{3/2}(x - \sqrt{0.  
0}%} -]=so zero while itreplace

$$ f(x) = \sqrt{3x - 5} $$, $$ h(x) = 2x^2 $$, and the composition (f ∘ f)(x)

Explore how to solve the composition of the radical function f(x) = √(3x - 5) with itself, known as (f ∘ f)(x). This step-by-step solution covers key concepts in algebra, including function composition and radical functions, making it ideal for high school students in Grades 10-12.

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