Math Problem Statement
Solution
Let's analyze the problem presented in the image.
Problem Breakdown:
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Functions Given:
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Function Composition:
- The function is defined for all , except for the interval .
Part (a) Calculate the values of and .
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To determine the values of and , we need to consider where the function is not defined.
- The function involves a square root, which means is only defined when , i.e., .
- Therefore, for to be defined, must satisfy .
Let's solve :
Now, factorize the quadratic expression:
The critical points are and . The quadratic expression changes signs at these points.
Analyzing the intervals:
- and make the expression non-negative.
- makes the expression negative.
Therefore, is not defined on the interval . So, and .
Part (b) Find the range of .
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The range of is the set of all possible values can take when lies in the domains where is defined, i.e., .
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For , . So, .
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As can take values from to infinity within the specified domain, will take values from to infinity.
Hence, the range of is .
Summary:
(a) The values of and are and .
(b) The range of is .
Would you like more details on any of the steps? Here are five questions you might explore further:
- How do you find the domain of a composite function?
- What are the properties of square root functions that influence their domains and ranges?
- How does factoring a quadratic equation help in finding the critical points?
- What would happen to the domain and range if or were different functions?
- Can you explain why the range of starts at 0 and extends to infinity?
Tip: Always analyze the domain of individual functions before dealing with their compositions, as this determines where the composition is defined.
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Math Problem Analysis
Mathematical Concepts
Algebra
Composite Functions
Quadratic Equations
Square Root Functions
Formulas
f(x) = √(x - 3)
g(x) = x² + 2x
Quadratic inequality: (x + 3)(x - 1) ≥ 0
Theorems
Domain of Composite Functions
Range of Square Root Functions
Suitable Grade Level
Grades 10-12
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