Math Problem Statement

The functions f and g are defined as f(x) = √(x - 3) and g(x) = x² + 2x. The function f ∘ g(x) is defined for all x ∈ ℝ, except for the interval ]a, b[. (a) Calculate the values of a and b. (b) Find the range of f ∘ g.

Solution

Let's analyze the problem presented in the image.

Problem Breakdown:

  1. Functions Given:

    • f(x)=x3f(x) = \sqrt{x - 3}
    • g(x)=x2+2xg(x) = x^2 + 2x
  2. Function Composition:

    • The function fg(x)f \circ g(x) is defined for all xRx \in \mathbb{R}, except for the interval ]a,b[]a, b[.

Part (a) Calculate the values of aa and bb.

  • To determine the values of aa and bb, we need to consider where the function f(g(x))f(g(x)) is not defined.

    • The function f(x)f(x) involves a square root, which means f(x)f(x) is only defined when x30x - 3 \geq 0, i.e., x3x \geq 3.
    • Therefore, for f(g(x))f(g(x)) to be defined, g(x)g(x) must satisfy g(x)3g(x) \geq 3.

    Let's solve g(x)3g(x) \geq 3:

    g(x)=x2+2xg(x) = x^2 + 2x x2+2x3x^2 + 2x \geq 3 x2+2x30x^2 + 2x - 3 \geq 0

    Now, factorize the quadratic expression: (x+3)(x1)0(x + 3)(x - 1) \geq 0

    The critical points are x=3x = -3 and x=1x = 1. The quadratic expression changes signs at these points.

    Analyzing the intervals:

    • x(,3]x \in (-\infty, -3] and x[1,)x \in [1, \infty) make the expression non-negative.
    • x(3,1)x \in (-3, 1) makes the expression negative.

    Therefore, f(g(x))f(g(x)) is not defined on the interval (3,1)(-3, 1). So, a=3a = -3 and b=1b = 1.

Part (b) Find the range of fgf \circ g.

  • The range of f(g(x))f(g(x)) is the set of all possible values f(g(x))f(g(x)) can take when xx lies in the domains where f(g(x))f(g(x)) is defined, i.e., x(,3][1,)x \in (-\infty, -3] \cup [1, \infty).

  • For x(,3][1,)x \in (-\infty, -3] \cup [1, \infty), g(x)3g(x) \geq 3. So, f(g(x))=g(x)3f(g(x)) = \sqrt{g(x) - 3}.

  • As g(x)g(x) can take values from 33 to infinity within the specified domain, f(g(x))f(g(x)) will take values from 00 to infinity.

    Hence, the range of fg(x)f \circ g(x) is [0,)[0, \infty).

Summary:

(a) The values of aa and bb are a=3a = -3 and b=1b = 1.

(b) The range of fg(x)f \circ g(x) is [0,)[0, \infty).


Would you like more details on any of the steps? Here are five questions you might explore further:

  1. How do you find the domain of a composite function?
  2. What are the properties of square root functions that influence their domains and ranges?
  3. How does factoring a quadratic equation help in finding the critical points?
  4. What would happen to the domain and range if f(x)f(x) or g(x)g(x) were different functions?
  5. Can you explain why the range of fgf \circ g starts at 0 and extends to infinity?

Tip: Always analyze the domain of individual functions before dealing with their compositions, as this determines where the composition is defined.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Composite Functions
Quadratic Equations
Square Root Functions

Formulas

f(x) = √(x - 3)
g(x) = x² + 2x
Quadratic inequality: (x + 3)(x - 1) ≥ 0

Theorems

Domain of Composite Functions
Range of Square Root Functions

Suitable Grade Level

Grades 10-12