Math Problem Statement

In the complex plane, solve problems related to points B(1+i) and C(-2+2i), and analyze the geometry of triangles and transformations.

Solution

Let's analyze and solve the questions from the image systematically.


Question 1:

Given points B(1+i)B(1 + i) and C(2+2i)C(-2 + 2i) in the complex plane.

(a) Find the affix of AA such that ABCABC forms a right isosceles triangle at AA:

  • AA must satisfy the condition for the triangle to be right and isosceles, meaning:
    1. AB=ACAB = AC.
    2. The angle at AA is 9090^\circ.

The affix zAz_A of AA satisfies: zAzB=zAzC|z_A - z_B| = |z_A - z_C| Using the distances: (xAxB)2+(yAyB)2=(xAxC)2+(yAyC)2.\sqrt{(x_A - x_B)^2 + (y_A - y_B)^2} = \sqrt{(x_A - x_C)^2 + (y_A - y_C)^2}. Solve for zAz_A.

(b) Construct ABCABC:

  • Use the affixes found in part (a) to determine the positions of AA, BB, and CC on the complex plane.

(c) Find the affix of EE, symmetric of AA with respect to the midpoint of [BC][BC]:

  • The midpoint of [BC][BC] is: M=zB+zC2.M = \frac{z_B + z_C}{2}. The symmetric point EE is: zE=2MzA.z_E = 2M - z_A.

Question 2:

ABCABC is a right isosceles triangle, direct in AA. aa and bb are the affixes of AA and BB.

(a) Find the affix of CC in terms of aa and bb:

Since ABCABC is direct and isosceles, the rotation of BB around AA by 9090^\circ gives CC: zC=zA+i(zBzA).z_C = z_A + i(z_B - z_A).

(b) Find the affix of DD in terms of aa and bb such that ABCDABCD forms a parallelogram:

In a parallelogram: zD=zC+zBzA.z_D = z_C + z_B - z_A.


Question 3:

Given A(zA=2)A(z_A = 2), B(zB=1+3i)B(z_B = 1 + \sqrt{3}i), and Z=zBzAZ = \frac{z_B}{z_A}.

(a) Write ZZ in exponential form:

Z=zBzA=1+3i2.Z = \frac{z_B}{z_A} = \frac{1 + \sqrt{3}i}{2}. Convert ZZ into the exponential form reiθre^{i\theta} by:

  1. Finding the modulus r=Zr = |Z|.
  2. Calculating the argument θ\theta using tan1(Im(Z)Re(Z))\tan^{-1}\left(\frac{\text{Im}(Z)}{\text{Re}(Z)}\right).

(b) Deduce the nature of the triangle OABOAB:

  • Compute the lengths OAOA, OBOB, and ABAB.
  • Use these to classify the triangle OABOAB (e.g., isosceles, equilateral, or scalene).

Would you like detailed solutions for all parts or a specific question? Let me know! Here are some follow-up questions:

  1. How do we verify if AA lies on the perpendicular bisector of BCBC?
  2. What are the exact coordinates of CC in Question 2(a)?
  3. How do we visualize the symmetry about the midpoint in Question 1(c)?
  4. How can the exponential form in Question 3(a) simplify ZZ?
  5. Can we classify ABCDABCD geometrically using complex numbers?

Tip:

Use geometric properties of complex numbers, like rotations and symmetries, to simplify these computations.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Distance and Midpoint Formulas
Geometry of Complex Planes
Rotation and Symmetry in Complex Numbers

Formulas

Distance formula: |z1 - z2|
Midpoint formula: M = (z1 + z2)/2
Rotation formula: z' = z0 + i(z - z0)

Theorems

Properties of isosceles right triangles
Symmetry and rotations in the complex plane
Parallelogram construction using complex affixes

Suitable Grade Level

Grades 11-12 or Pre-University