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The problem asks which sign (greater than `>` or less than `<`) makes the statement true:

\[
-\sqrt{3} \, ? \, -\frac{11}{10}
\]

Let's evaluate both sides.

1. **Evaluate \(-\sqrt{3}\):**
   - The square root of 3 is approximately \( \sqrt{3} \approx 1.732 \).
   - Therefore, \( -\sqrt{3} \approx -1.732 \).

2. **Evaluate \(-\frac{11}{10}\):**
   - \( -\frac{11}{10} = -1.1 \).

Now, compare the two values:
- \( -1.732 \) is less than \( -1.1 \).

Thus, the correct sign to make the statement true is `<`.

So the complete statement is:
\[
-\sqrt{3} < -\frac{11}{10}
\]

Would you like any more details or have any other questions?

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Here are 5 related questions to consider:
1. What is the value of \( \sqrt{2} \) and how does it compare to \( -\frac{5}{4} \)?
2. How would you express \( \frac{11}{10} \) as a decimal?
3. Can you explain why negative square roots are always less than their positive counterparts?
4. How would you determine the correct sign for \( -\frac{3}{2} \) and \( -1.5 \)?
5. What is the approximate decimal value of \( \sqrt{5} \) and how does it compare to \( 2 \)?

**Tip:** Remember that when comparing negative numbers, the one with the smaller absolute value is actually greater.

Which sign makes the statement true? -√3 ? -11/10

Understand how to determine the correct inequality sign between -√3 and -11/10. This problem focuses on comparing square roots and negative numbers, and is suitable for students in Grades 6-8.

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