To determine how much longer the high school's pool is compared to the community pool, we can follow these steps:

1. Identify the given information:

• Community Pool:

  • Volume: $480,000 \, \text{liters} = 480 \, \text{cubic meters}$
  • Width: $12 \, \text{meters}$
  • Depth: $2 \, \text{meters}$

• High School Pool:

  • Volume: $937,500 \, \text{liters} = 937.5 \, \text{cubic meters}$
  • Width: $15 \, \text{meters}$
  • Depth: $2.5 \, \text{meters}$

2. Use the formula for volume of a rectangular prism:

$\text{Volume} = \text{Length} \times \text{Width} \times \text{Depth}$

3. Calculate the length of each pool:

• Community Pool: $480 = \text{Length} \times 12 \times 2$ Solving for the length: $\text{Length} = \frac{480}{12 \times 2} = \frac{480}{24} = 20 \, \text{meters}$

• High School Pool: $937.5 = \text{Length} \times 15 \times 2.5$ Solving for the length: $\text{Length} = \frac{937.5}{15 \times 2.5} = \frac{937.5}{37.5} = 25 \, \text{meters}$

4. Find the difference in length:

$25 - 20 = 5 \, \text{meters}$

The high school's pool is 5 meters longer than the community pool.

Would you like further details or explanations on this? Here are some additional questions that build on this problem:

1. What would be the volume of the community pool if its length was increased by 5 meters?
2. How much water would need to be added if the community pool was expanded to the same size as the high school pool?
3. If the high school's pool depth was reduced to match the community pool, how long would the pool need to be to maintain the same volume?
4. What would happen to the pool's volume if the width of the high school pool increased by 3 meters but the length stayed the same?
5. How does the shape of the pool affect its capacity for swimmers?

Tip: When solving problems involving volume, always ensure you use consistent units, especially when converting between liters and cubic meters!