The problem you've provided describes a right-angled triangular plot of land, where the lengths of the two perpendicular sides are given as 220 meters and 100 meters. There is a swimming pool in the shape of a rectangular prism (with a rectangular base) being built inside the plot. The base of the pool is a square, with two sides of the pool aligned with the perpendicular sides of the triangular plot. Additionally, one of the pool’s corners touches the hypotenuse of the triangular plot. The depth of the pool is given as 1.6 meters.

We are tasked with finding the volume of the pool.

Solution Outline:

1. Dimensions of the Pool's Base: The base of the pool is square-shaped. Since two sides of the pool are parallel to the plot's perpendicular sides, the side length of the pool's base will be the shortest of the two side lengths of the triangle, i.e., 100 meters.

2. Volume of the Pool: The volume of a rectangular prism is calculated as: $\text{Volume} = \text{Base Area} \times \text{Height}$ Here:

   • The base is a square, so its area is: $\text{Base Area} = 100 \times 100 = 10,000 \text{ square meters}$
   • The height (or depth of the pool) is 1.6 meters.

   So the volume of the pool is: $\text{Volume} = 10,000 \times 1.6 = 16,000 \text{ cubic meters}$

Thus, the volume of the swimming pool is 16,000 cubic meters.

Would you like further details on any step? Here are five related questions for practice:

1. How do we calculate the hypotenuse of the triangular plot?
2. What would the volume be if the depth were 2 meters?
3. How do we calculate the area of the triangular plot of land?
4. If the base of the pool was a rectangle instead of a square, how would the volume calculation change?
5. What is the perimeter of the triangular plot?

Tip: For geometric problems, it's crucial to identify the shapes involved and how they relate to one another in terms of dimensions.